
Find the interval for which $f\left( x \right)=\sin x$ is one-one $\left[ 0,\pi \right]$
Answer
533.4k+ views
Hint: To solve this question we need to know the concept of differentiation. A function is said to be one-one when that function maps distinct elements of its domain to distinct elements of its codomain. This type of function is also called an injective function. Differentiation of $\sin x$ is $\cos x$
The function $\cos x$ is positive only in the first and fourth quadrant.
Complete step by step solution:
The question asks us to find the interval in which the function $\sin x$ is one-one when angle $x$ is in the interval$\left[ 0,\pi \right]$.
The first part is to differentiate the function so as to find the interval in which the function comes to be one-one. On differentiating the function $f\left( x \right)=\sin x$ with respect to x, we get:
$f'\left( x \right)=\dfrac{d\left( f\left( x \right) \right)}{dx}$
Here $f\left( x \right)$ is $\sin x$, on differentiating we get:
$\Rightarrow \dfrac{d\left( \sin x \right)}{dx}$
The differentiation of the function $\sin x$ is $\cos x$ , so putting the value we get:
$\Rightarrow \cos x$
Now for $f\left( x \right)$ to be one-one, $f\left( x \right)$ has to be strictly increasing or increasing, which means or mathematically would be written as $f'\left( x \right)\ge 0$ or $f'\left( x \right)>0$ respectively.
We have got $f'\left( x \right)=\cos x$ , for function to be one-one value of $cos x$ should be greater than equal to zero, which would be written as:
$\cos x\ge 0$
So the value of $\cos x$ will be positive when the value of $x$in the interval$\left[ 0,\dfrac{\pi }{2} \right]$.
$\therefore $The interval for which $f\left( x \right)=\sin x$ is one-one $\left[ 0,\pi \right]$ is $\left[ 0,\dfrac{\pi }{2} \right]$.
Note: We need to know the formula of differentiation to solve the question. There are many applications of derivatives and finding the function to be one-one is one of them. We should know where the trigonometric function will give the positive or negative value. Always keep in mind that in a one-one function the answer never repeats for any value in a certain interval.
The function $\cos x$ is positive only in the first and fourth quadrant.
Complete step by step solution:
The question asks us to find the interval in which the function $\sin x$ is one-one when angle $x$ is in the interval$\left[ 0,\pi \right]$.
The first part is to differentiate the function so as to find the interval in which the function comes to be one-one. On differentiating the function $f\left( x \right)=\sin x$ with respect to x, we get:
$f'\left( x \right)=\dfrac{d\left( f\left( x \right) \right)}{dx}$
Here $f\left( x \right)$ is $\sin x$, on differentiating we get:
$\Rightarrow \dfrac{d\left( \sin x \right)}{dx}$
The differentiation of the function $\sin x$ is $\cos x$ , so putting the value we get:
$\Rightarrow \cos x$
Now for $f\left( x \right)$ to be one-one, $f\left( x \right)$ has to be strictly increasing or increasing, which means or mathematically would be written as $f'\left( x \right)\ge 0$ or $f'\left( x \right)>0$ respectively.
We have got $f'\left( x \right)=\cos x$ , for function to be one-one value of $cos x$ should be greater than equal to zero, which would be written as:
$\cos x\ge 0$
So the value of $\cos x$ will be positive when the value of $x$in the interval$\left[ 0,\dfrac{\pi }{2} \right]$.
$\therefore $The interval for which $f\left( x \right)=\sin x$ is one-one $\left[ 0,\pi \right]$ is $\left[ 0,\dfrac{\pi }{2} \right]$.
Note: We need to know the formula of differentiation to solve the question. There are many applications of derivatives and finding the function to be one-one is one of them. We should know where the trigonometric function will give the positive or negative value. Always keep in mind that in a one-one function the answer never repeats for any value in a certain interval.
Recently Updated Pages
Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 Physics: Engaging Questions & Answers for Success

Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Business Studies: Engaging Questions & Answers for Success

Trending doubts
Which are the Top 10 Largest Countries of the World?

What are the major means of transport Explain each class 12 social science CBSE

Draw a labelled sketch of the human eye class 12 physics CBSE

Why cannot DNA pass through cell membranes class 12 biology CBSE

Differentiate between insitu conservation and exsitu class 12 biology CBSE

Draw a neat and well labeled diagram of TS of ovary class 12 biology CBSE

