
How do you find the intercepts of \[y = 2{x^2} - 5x + 2\] ?
Answer
546.3k+ views
Hint: Here in this question, we have to plot the graph for the equation. By substituting the x is equal to zero we can find the y intercept value and substituting y is equal to zero we can find the x intercept value. By equating the given equation to the general equation of line we can determine the slope. Here we have found the x intercepts.
Complete step by step solution:
An intercept is a point where the straight line or a curve intersects the y-axis in a plane. If the point x is zero then the obtained point is a y -intercept.
Now consider the given equation \[y = 2{x^2} - 5x + 2\] -----------(1)
Substitute the value of y as 0 in the equation (1) then we have
\[ \Rightarrow 0 = 2{x^2} - 5x + 2\]
To determine the value of x we use the formula \[x = \dfrac{{ - b \pm \sqrt {{b^2} - 4ac} }}{{2a}}\]. Here the value of a is 2 and the value of b is -5 and the value of c is 2
Hence by substituting these values in the formula we get
\[ \Rightarrow x = \dfrac{{ - ( - 5) \pm \sqrt {{{( - 5)}^2} - 4(2)(2)} }}{{2(2)}}\]
On simplifying we get
\[ \Rightarrow x = \dfrac{{5 \pm \sqrt {25 - 16} }}{4}\]
On subtracting 16 from 25 we get
\[ \Rightarrow x = \dfrac{{5 \pm \sqrt 9 }}{4}\]
The square root of 9 is 3
\[ \Rightarrow x = \dfrac{{5 \pm 3}}{4}\]
Therefore, we have \[x = \dfrac{{5 + 3}}{4}\] and \[x = \dfrac{{5 - 3}}{4}\]
On simplifying we get
\[x = \dfrac{8}{4} = 2\] and \[x = \dfrac{{5 - 3}}{4} = \dfrac{1}{2}\]
Therefore, x-intercept are \[\left( {2,0} \right)\] and \[\left( {\dfrac{1}{2},0} \right)\]
We can also find the y- intercept
Substitute the value of x as 0 in equation (1), then we have
\[ \Rightarrow y = 2{(0)^2} - 5(0) + 2\]
On simplifying we get
\[ \Rightarrow y = 2\]
Therefore, y-intercept is \[\left( {0,2} \right)\]
Hence we have found the x intercepts and also the y intercepts.
The graph for this is given below
Note: The question is belonging to the concept of graph. By comparing the given equation to the equation of a line we calculate the slope and intercept. Or by choosing the value of x we can determine the value of y and then plotting the graphs for these points we obtain the result.
Complete step by step solution:
An intercept is a point where the straight line or a curve intersects the y-axis in a plane. If the point x is zero then the obtained point is a y -intercept.
Now consider the given equation \[y = 2{x^2} - 5x + 2\] -----------(1)
Substitute the value of y as 0 in the equation (1) then we have
\[ \Rightarrow 0 = 2{x^2} - 5x + 2\]
To determine the value of x we use the formula \[x = \dfrac{{ - b \pm \sqrt {{b^2} - 4ac} }}{{2a}}\]. Here the value of a is 2 and the value of b is -5 and the value of c is 2
Hence by substituting these values in the formula we get
\[ \Rightarrow x = \dfrac{{ - ( - 5) \pm \sqrt {{{( - 5)}^2} - 4(2)(2)} }}{{2(2)}}\]
On simplifying we get
\[ \Rightarrow x = \dfrac{{5 \pm \sqrt {25 - 16} }}{4}\]
On subtracting 16 from 25 we get
\[ \Rightarrow x = \dfrac{{5 \pm \sqrt 9 }}{4}\]
The square root of 9 is 3
\[ \Rightarrow x = \dfrac{{5 \pm 3}}{4}\]
Therefore, we have \[x = \dfrac{{5 + 3}}{4}\] and \[x = \dfrac{{5 - 3}}{4}\]
On simplifying we get
\[x = \dfrac{8}{4} = 2\] and \[x = \dfrac{{5 - 3}}{4} = \dfrac{1}{2}\]
Therefore, x-intercept are \[\left( {2,0} \right)\] and \[\left( {\dfrac{1}{2},0} \right)\]
We can also find the y- intercept
Substitute the value of x as 0 in equation (1), then we have
\[ \Rightarrow y = 2{(0)^2} - 5(0) + 2\]
On simplifying we get
\[ \Rightarrow y = 2\]
Therefore, y-intercept is \[\left( {0,2} \right)\]
Hence we have found the x intercepts and also the y intercepts.
The graph for this is given below
Note: The question is belonging to the concept of graph. By comparing the given equation to the equation of a line we calculate the slope and intercept. Or by choosing the value of x we can determine the value of y and then plotting the graphs for these points we obtain the result.
Recently Updated Pages
Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Trending doubts
There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

Discuss the various forms of bacteria class 11 biology CBSE

Explain zero factorial class 11 maths CBSE

What organs are located on the left side of your body class 11 biology CBSE

Draw a labelled diagram of the human heart and label class 11 biology CBSE

What is 1s 2s 2p 3s 3p class 11 chemistry CBSE

