Find the hydrolysis product when a phosphodiester bond of nucleotide breaks.
(A) $3 - {\text{OH}} - {\text{deoxyribose}} - 5 - {\text{PO}}_4^{3 - }$
(B) $5 - {\text{OH}} - {\text{deoxyribose}} - 3 - {\text{PO}}_4^{3 - }$
(C) $2 - {\text{OH}} - {\text{deoxyribose}} - 2 - {\text{PO}}_4^{3 - }$
(D) $4 - {\text{OH}} - {\text{deoxyribose}} - 2 - {\text{PO}}_4^{3 - }$
Answer
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Hint: In nucleotides, the nitrogenous base and the five carbon sugars are linked through a glycosidic bond and are collectively known as a nucleoside. The phosphate group is linked to the nucleoside through a phosphodiester bond. The hydrolysis of phosphodiester bond means adding water molecules through the phosphodiester bond.
Complete Step by step answer: We know that a nucleotide is made of three subunits: a five-carbon sugar, a nitrogenous base and one phosphate group.
The nitrogenous base is linked to the five-carbon sugar through glycosidic bond. The nitrogenous base and the five carbon sugar is collectively known as a nucleoside. The phosphate group is linked to the nucleoside through a phosphodiester bond. The phosphate group is linked to the nucleoside at $5' - {\text{OH}}$ end. Thus, the phosphodiester bond is a strong covalent bond between a phosphate group and two other molecules.
In nucleotides, the phosphodiester bond is the linkage between the third $\left( {\text{3}} \right)$ carbon atom of one sugar molecule and the fifth $\left( {\text{5}} \right)$ carbon atom of another sugar molecule.
The hydrolysis of phosphodiester bond is as follows:
From the reaction, we can see that the hydroxyl $\left( { - {\text{OH}}} \right)$ group is at the third carbon $\left( {\text{3}} \right)$ and the phosphate group is at the fifth carbon of the deoxyribose sugar.
Thus, when the phosphodiester bond is hydrolysed, the phosphodiester bond breaks and forms $3 - {\text{OH}} - {\text{deoxyribose}} - 5 - {\text{PO}}_4^{3 - }$.
Thus, the correct option is (A) $3 - {\text{OH}} - {\text{deoxyribose}} - 5 - {\text{PO}}_4^{3 - }$.
Note: The basic building blocks of nucleic acids are known as nucleotides. Nucleotides are made up of nucleosides and phosphate. Nucleotides play an important role in the metabolism. The hydrolysis of phosphodiester bonds is catalysed by the enzyme phosphodiesterases.
Complete Step by step answer: We know that a nucleotide is made of three subunits: a five-carbon sugar, a nitrogenous base and one phosphate group.
The nitrogenous base is linked to the five-carbon sugar through glycosidic bond. The nitrogenous base and the five carbon sugar is collectively known as a nucleoside. The phosphate group is linked to the nucleoside through a phosphodiester bond. The phosphate group is linked to the nucleoside at $5' - {\text{OH}}$ end. Thus, the phosphodiester bond is a strong covalent bond between a phosphate group and two other molecules.
In nucleotides, the phosphodiester bond is the linkage between the third $\left( {\text{3}} \right)$ carbon atom of one sugar molecule and the fifth $\left( {\text{5}} \right)$ carbon atom of another sugar molecule.
The hydrolysis of phosphodiester bond is as follows:
From the reaction, we can see that the hydroxyl $\left( { - {\text{OH}}} \right)$ group is at the third carbon $\left( {\text{3}} \right)$ and the phosphate group is at the fifth carbon of the deoxyribose sugar.
Thus, when the phosphodiester bond is hydrolysed, the phosphodiester bond breaks and forms $3 - {\text{OH}} - {\text{deoxyribose}} - 5 - {\text{PO}}_4^{3 - }$.
Thus, the correct option is (A) $3 - {\text{OH}} - {\text{deoxyribose}} - 5 - {\text{PO}}_4^{3 - }$.
Note: The basic building blocks of nucleic acids are known as nucleotides. Nucleotides are made up of nucleosides and phosphate. Nucleotides play an important role in the metabolism. The hydrolysis of phosphodiester bonds is catalysed by the enzyme phosphodiesterases.
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