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# Find the difference between the compound interest compounded yearly and half-yearly on Rs. 10000 for 18 months at 10% per annum.

Last updated date: 16th Sep 2024
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Hint: First, find the amount for the compound interest compounded yearly by applying the formula $A = P{\left( {1 + \dfrac{r}{{100}}} \right)^t}$ for the first year and then the formula $A = P{\left( {1 + \dfrac{r}{{2 \times 100}}} \right)^{t \times 2}}$ for the next 6 months. Then subtract the principal from the amount to get the interest.
Then, find the amount for the compound interest compounded half-yearly by applying the formula $A = P{\left( {1 + \dfrac{r}{{2 \times 100}}} \right)^{t \times 2}}$. Then subtract the principal from the amount to get the interest. After that subtract the values of the interest to find the difference of the interest.

The formula for compound interest compounded yearly is,
$A = P{\left( {1 + \dfrac{r}{{100}}} \right)^t}$
The formula for compound interest compounded half-yearly is,
$A = P{\left( {1 + \dfrac{r}{{2 \times 100}}} \right)^{t \times 2}}$
Given: - Principal, P = Rs. 10000
Time, t = 18 months = 1.5 years
Rate, r = 10% p.a.
For the compound interest compounded yearly,
Calculate the amount for 1 year. Then calculate the amount for $\dfrac{1}{2}$ year.
For 1st year,
$P = 10000$
$t = 1$
$r = 10\%$
Then,
$A = 10000{\left( {1 + \dfrac{{10}}{{100}}} \right)^1}$
Cancel out common factors and take LCM,
$\Rightarrow A = 10000\left( {\dfrac{{10 + 1}}{{10}}} \right)$
Add the terms and cancel out the common factor,
$\Rightarrow A = 1000 \times 11$
Multiply the terms,
$\Rightarrow A = 11000$
Now, for $\dfrac{1}{2}$ year,
$P = 11000$
$r = 10\%$
$t = \dfrac{1}{2}$
Substitute the values in the formula for compounded half-yearly,
$A = 11000{\left( {1 + \dfrac{{10}}{{2 \times 100}}} \right)^{\dfrac{1}{2} \times 2}}$
Cancel out the common factors,
$\Rightarrow A = 11000{\left( {1 + \dfrac{1}{{20}}} \right)^1}$
Take LCM,
$\Rightarrow A = 11000 \times \dfrac{{20 + 1}}{{20}}$
Cancel out the common factors,
$\Rightarrow A = 550 \times 21$
Multiply the terms,
$\Rightarrow A = {\text{Rs}}{\text{. }}11550$
So, the interest is,
$I = A - P$
Substitute the value of amount and principal,
$\Rightarrow I = 11550 - 10000$
Subtract the term,
$\Rightarrow I = {\text{Rs}}{\text{. }}1550$.....….. (1)
For the compound interest compounded half-yearly,
$P = 10000$
$r = 10\%$
$t = \dfrac{3}{2}$
Substitute the values in the formula for compounded half-yearly,
$A = 10000{\left( {1 + \dfrac{{10}}{{2 \times 100}}} \right)^{\dfrac{3}{2} \times 2}}$
Cancel out the common factors,
$\Rightarrow A = 10000{\left( {1 + \dfrac{1}{{20}}} \right)^3}$
Take LCM,
$\Rightarrow A = 10000{\left( {\dfrac{{20 + 1}}{{20}}} \right)^3}$
$\Rightarrow A = 10000 \times \dfrac{{21}}{{20}} \times \dfrac{{21}}{{20}} \times \dfrac{{21}}{{20}}$
Cancel the terms and multiply the remaining terms,
$\Rightarrow A = {\text{Rs}}{\text{. }}11576.25$
So, the interest is,
$I = A - P$
Substitute the value of amount and principal,
$\Rightarrow I = 11576.25 - 10000$
Subtract the term,
$\Rightarrow I = {\text{Rs}}{\text{. }}1576.25$..........….. (2)
For the difference between two compound interest is,
$\therefore 1576.25 - 1550 = {\text{Rs}}{\text{. 2}}6.25$

Hence, the difference between the compound interest compounded yearly and half-yearly is Rs. 26.25.

Note: The students might make mistakes in calculating the amount for the 6 months compounded yearly.
Compound interest is the interest calculated on the principal and the interest accumulated over the previous period. It is different from the simple interest where interest is not added to the principal while calculating the interest during the next period.