Find the curved surface area (CSA) of the hemisphere if the volume is $2425\dfrac{1}{2}{m^3}$.
Answer
641.4k+ views
Hint – In order to solve this problem, firstly find the radius of the hemisphere with the help of the given volume then calculate its curved surface area by using the formula $2\pi {r^2}$.
Complete step by step answer:
We know the volume of the hemisphere of radius r is $\dfrac{2}{3}\pi {r^3}$. ……(1)
The given volume is $2425\dfrac{1}{2}{m^3}$. ……(2)
So, we can equate (1) and (2),
$\dfrac{2}{3}\pi {r^3} = 2425\dfrac{1}{2}$ ……(3)
As we know, ${\text{a}}\dfrac{{\text{b}}}{{\text{c}}}{\text{ = }}\dfrac{{{\text{ac + b}}}}{{\text{c}}}$ the same we will do with $2425\dfrac{1}{2}$.
Therefore,
$2425\dfrac{1}{2} = \dfrac{{2425(2) + 1}}{2} = \dfrac{{4851}}{2}$ …….(4)
From (3) and (4) we can say that,
$\dfrac{2}{3}\pi {r^3} = \dfrac{{4851}}{2}$ [Use $\pi = \dfrac{{22}}{7}$]
On solving it further to get the value of r we get,
$
{{\text{r}}^{\text{3}}{\text{ = }}\dfrac{4851 \times 7 \times 3}{2 \times 2 \times 22}} \\
{{\text{r}}^{\text{3}}}{\text{ = 1157}}{\text{.625}} \\
{{\text{r}}^{\text{3}}}{\text{ = }}\,{{\text{(10}}{\text{.5)}}^{\text{3}}} \\
{\text{r = 10}}{\text{.5}} \\
$
Therefore the radius of the hemisphere is 10.5 m.
The curved surface area of the hemisphere is $2\pi {r^2}$. So, using the formula of CSA of hemisphere we get,
$
CSA = 2\pi {r^2} = \,2 \times \dfrac{{22}}{7} \times {(10.5)^2} = \dfrac{{44}}{7} \times 110.25 \\
CSA = \dfrac{{44}}{7} \times 110.25 = 693{m^2} \\
$
Hence the curved surface area of the hemisphere is 693 ${{\text{m}}^{\text{2}}}$.
Note – Whenever you face such types of problems with hemispheres or circles you just need to know one of the parameters that is radius. Since by knowing radius you can calculate their areas, volumes etc. Here we have given the volume and asked to find the CSA of the hemisphere. We have obtained the radius using the formula of volume then we have obtained the CSA of hemisphere using the formula of CSA. Doing this will take you to the right answer.
Complete step by step answer:
We know the volume of the hemisphere of radius r is $\dfrac{2}{3}\pi {r^3}$. ……(1)
The given volume is $2425\dfrac{1}{2}{m^3}$. ……(2)
So, we can equate (1) and (2),
$\dfrac{2}{3}\pi {r^3} = 2425\dfrac{1}{2}$ ……(3)
As we know, ${\text{a}}\dfrac{{\text{b}}}{{\text{c}}}{\text{ = }}\dfrac{{{\text{ac + b}}}}{{\text{c}}}$ the same we will do with $2425\dfrac{1}{2}$.
Therefore,
$2425\dfrac{1}{2} = \dfrac{{2425(2) + 1}}{2} = \dfrac{{4851}}{2}$ …….(4)
From (3) and (4) we can say that,
$\dfrac{2}{3}\pi {r^3} = \dfrac{{4851}}{2}$ [Use $\pi = \dfrac{{22}}{7}$]
On solving it further to get the value of r we get,
$
{{\text{r}}^{\text{3}}{\text{ = }}\dfrac{4851 \times 7 \times 3}{2 \times 2 \times 22}} \\
{{\text{r}}^{\text{3}}}{\text{ = 1157}}{\text{.625}} \\
{{\text{r}}^{\text{3}}}{\text{ = }}\,{{\text{(10}}{\text{.5)}}^{\text{3}}} \\
{\text{r = 10}}{\text{.5}} \\
$
Therefore the radius of the hemisphere is 10.5 m.
The curved surface area of the hemisphere is $2\pi {r^2}$. So, using the formula of CSA of hemisphere we get,
$
CSA = 2\pi {r^2} = \,2 \times \dfrac{{22}}{7} \times {(10.5)^2} = \dfrac{{44}}{7} \times 110.25 \\
CSA = \dfrac{{44}}{7} \times 110.25 = 693{m^2} \\
$
Hence the curved surface area of the hemisphere is 693 ${{\text{m}}^{\text{2}}}$.
Note – Whenever you face such types of problems with hemispheres or circles you just need to know one of the parameters that is radius. Since by knowing radius you can calculate their areas, volumes etc. Here we have given the volume and asked to find the CSA of the hemisphere. We have obtained the radius using the formula of volume then we have obtained the CSA of hemisphere using the formula of CSA. Doing this will take you to the right answer.
Recently Updated Pages
Master Class 10 Computer Science: Engaging Questions & Answers for Success

Master Class 10 General Knowledge: Engaging Questions & Answers for Success

Master Class 10 English: Engaging Questions & Answers for Success

Master Class 10 Social Science: Engaging Questions & Answers for Success

Master Class 10 Maths: Engaging Questions & Answers for Success

Master Class 10 Science: Engaging Questions & Answers for Success

Trending doubts
Find the sum of series 1 + 2 + 3 + 4 + 5 + + 100 class 9 maths CBSE

Fill the blanks with the suitable prepositions 1 The class 9 english CBSE

Difference Between Plant Cell and Animal Cell

What is the Full Form of ICSE / ISC ?

What is pollution? How many types of pollution? Define it

Name 10 Living and Non living things class 9 biology CBSE

