Find the cube root of the following number by prime factorization method: $10648$
Answer
644.7k+ views
Hint: Prime factorization is the process of finding which prime numbers can be multiplied together to make the original number, where prime numbers are the numbers greater than $1$ and which are not the product of any two smaller natural numbers. For Example: $2,{\text{ 3, 5, 7,}}......$ $2$ is the prime number as it can have only $1$ factor. Factors are the number $1$and the number itself. Cube root of any number is the factor which is multiplied with it- self three times.
Complete step by step answer:
To find the prime factorisation, start dividing the given number $10648$by the first prime number,$2$ Continue division until it is not divisible by$2$. Gradually start dividing by $3,{\text{ 5, 7, 11, 13,}}....$
Let’s start dividing the given number $10648$by $2$
$
10648 \div 2 = 5324 \\
5324 \div 2 = 2662 \\
2662 \div 2 = 1331 \\
1331 \div 2 = 665.5 \\
$
So, $1331$ is further not divided by$2$. Hence, $10648 = 2 \times 2 \times 2 \times 1331$
Now take, the second prime number, $3$ and divide
$1331 \div 3 = 443.6667$
So, $1331$ is not divisible by$3$. Therefore $3$ is not the factor.
Now, divide $1331{\text{ by 5}}$
$1331 \div 5 = 266.2$
As $1331$ is not divisible by $5$ and therefore $5$ is not the factor.
Now, divide $1331$ by $7$
$1331 \div 7 = 190.1429$
As, $1331$ is not divisible by$7$. Therefore $7$ is not the factor.
Now, divide $1331$ by $11$
$
1331 \div 11 = 121 \\
121 \div 11 = 11 \\
11 \div 11 = 1 \\
$
Therefore $11$ is the factor. And $1331 = 11 \times 11 \times 11$
Now, taking the given number-
$10648 = 2 \times 2 \times 2 \times 11 \times 11 \times 11$
Taking cube roots both the sides,
\[\sqrt[3]{{10648}} = \sqrt[3]{{2 \times 2 \times 2 \times 11 \times 11 \times 11}}\]
As per the definition we can write –
$
{2^3} = 2 \times 2 \times 2 \\
{11^3} = 11 \times 11 \times 11 \\
$
\[\sqrt[3]{{10648}} = \sqrt[3]{{{2^3} \times {{11}^3}}}\]
As, Cubes and cube-roots cancel each other-
\[
\sqrt[3]{{10648}} = 2 \times 11 \\
\sqrt[3]{{10648}} = 22 \\
\]
Thus, the cube-root of $10648$ is $22$. This is the required solution.
Note: Another method to find the prime factorization is to use the factor tree. A factor tree is the tool that breaks down any number into its prime factors.
Complete step by step answer:
To find the prime factorisation, start dividing the given number $10648$by the first prime number,$2$ Continue division until it is not divisible by$2$. Gradually start dividing by $3,{\text{ 5, 7, 11, 13,}}....$
Let’s start dividing the given number $10648$by $2$
$
10648 \div 2 = 5324 \\
5324 \div 2 = 2662 \\
2662 \div 2 = 1331 \\
1331 \div 2 = 665.5 \\
$
So, $1331$ is further not divided by$2$. Hence, $10648 = 2 \times 2 \times 2 \times 1331$
Now take, the second prime number, $3$ and divide
$1331 \div 3 = 443.6667$
So, $1331$ is not divisible by$3$. Therefore $3$ is not the factor.
Now, divide $1331{\text{ by 5}}$
$1331 \div 5 = 266.2$
As $1331$ is not divisible by $5$ and therefore $5$ is not the factor.
Now, divide $1331$ by $7$
$1331 \div 7 = 190.1429$
As, $1331$ is not divisible by$7$. Therefore $7$ is not the factor.
Now, divide $1331$ by $11$
$
1331 \div 11 = 121 \\
121 \div 11 = 11 \\
11 \div 11 = 1 \\
$
Therefore $11$ is the factor. And $1331 = 11 \times 11 \times 11$
Now, taking the given number-
$10648 = 2 \times 2 \times 2 \times 11 \times 11 \times 11$
Taking cube roots both the sides,
\[\sqrt[3]{{10648}} = \sqrt[3]{{2 \times 2 \times 2 \times 11 \times 11 \times 11}}\]
As per the definition we can write –
$
{2^3} = 2 \times 2 \times 2 \\
{11^3} = 11 \times 11 \times 11 \\
$
\[\sqrt[3]{{10648}} = \sqrt[3]{{{2^3} \times {{11}^3}}}\]
As, Cubes and cube-roots cancel each other-
\[
\sqrt[3]{{10648}} = 2 \times 11 \\
\sqrt[3]{{10648}} = 22 \\
\]
Thus, the cube-root of $10648$ is $22$. This is the required solution.
Note: Another method to find the prime factorization is to use the factor tree. A factor tree is the tool that breaks down any number into its prime factors.
Recently Updated Pages
Basicity of sulphurous acid and sulphuric acid are

Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 Biology: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Trending doubts
What is the Total Duration of Football Match?

Explain the Treaty of Vienna of 1815 class 10 social science CBSE

In football, which nation is called "La Roja"?

Why is there a time difference of about 5 hours between class 10 social science CBSE

10 examples of evaporation in daily life with explanations

What is the full form of POSCO class 10 social science CBSE

