
: Find principal and general solution of the equation $ \cot x = - \sqrt 3 $
Answer
577.5k+ views
Hint: In the given problem, to find the principal solution of the given equation we will use the value of trigonometric function $ \tan x $ for particular angle and also we will use basic knowledge of signs of trigonometric functions. To find a general solution of the given equation, we will use the result which is given by $ \tan x = \tan y \Rightarrow x = n\pi + y $ where $ n $ is integer.
Complete step-by-step answer:
In this problem, we have to find the principal and general solution of the equation $ \cot x = - \sqrt 3 $ . We know that $ \tan x = \dfrac{1}{{\cot x}} $ . Hence, we can write $ \tan x = - \dfrac{1}{{\sqrt 3 }} \cdots \cdots \left( 1 \right) $ .
In the equation $ \left( 1 \right) $ the value of $ \tan x $ is negative. Also we know that the trigonometric function $ \tan x $ is negative in the second and fourth quadrant. So, we can say that $ x $ will be in the second and fourth quadrant. Also we know that $ \tan x = \dfrac{1}{{\sqrt 3 }} \Rightarrow x = \dfrac{\pi }{6} $ .
In the second quadrant, we can say that
$
x = \pi - \dfrac{\pi }{6} \\
\Rightarrow x = \dfrac{{5\pi }}{6} \;
$
In the fourth quadrant, we can say that
$
x = 2\pi - \dfrac{\pi }{6} \\
\Rightarrow x = \dfrac{{11\pi }}{6} \;
$
Hence, principal solutions of the equation $ \cot x = - \sqrt 3 $ are $ x = \dfrac{{5\pi }}{6} $ and $ x = \dfrac{{11\pi }}{6} $ .
Now from the equation $ \left( 1 \right) $ , we can write $ \tan x = \tan \dfrac{{5\pi }}{6} \cdots \cdots \left( 2 \right) $ . We know that $ \tan x = \tan y \Rightarrow x = n\pi + y $ where $ n $ is integer. Use this information in equation $ \left( 2 \right) $ . So, we can write $ x = n\pi + \dfrac{{5\pi }}{6} $ where $ n $ is integer.
Hence, the general solution of the equation $ \cot x = - \sqrt 3 $ is $ x = n\pi + \dfrac{{5\pi }}{6} $ where $ n $ is integer.
Note: The solutions of a trigonometric equation for which $ 0 \leqslant x \leqslant 2\pi $ are called principal solutions. The mathematical expression involving integer $ n $ which gives all solutions of a trigonometric equation is called the general solution. In this type of problem, we must remember the values of trigonometric functions for particular angles. Also we must remember some trigonometric identities, results and formulas.
Complete step-by-step answer:
In this problem, we have to find the principal and general solution of the equation $ \cot x = - \sqrt 3 $ . We know that $ \tan x = \dfrac{1}{{\cot x}} $ . Hence, we can write $ \tan x = - \dfrac{1}{{\sqrt 3 }} \cdots \cdots \left( 1 \right) $ .
In the equation $ \left( 1 \right) $ the value of $ \tan x $ is negative. Also we know that the trigonometric function $ \tan x $ is negative in the second and fourth quadrant. So, we can say that $ x $ will be in the second and fourth quadrant. Also we know that $ \tan x = \dfrac{1}{{\sqrt 3 }} \Rightarrow x = \dfrac{\pi }{6} $ .
In the second quadrant, we can say that
$
x = \pi - \dfrac{\pi }{6} \\
\Rightarrow x = \dfrac{{5\pi }}{6} \;
$
In the fourth quadrant, we can say that
$
x = 2\pi - \dfrac{\pi }{6} \\
\Rightarrow x = \dfrac{{11\pi }}{6} \;
$
Hence, principal solutions of the equation $ \cot x = - \sqrt 3 $ are $ x = \dfrac{{5\pi }}{6} $ and $ x = \dfrac{{11\pi }}{6} $ .
Now from the equation $ \left( 1 \right) $ , we can write $ \tan x = \tan \dfrac{{5\pi }}{6} \cdots \cdots \left( 2 \right) $ . We know that $ \tan x = \tan y \Rightarrow x = n\pi + y $ where $ n $ is integer. Use this information in equation $ \left( 2 \right) $ . So, we can write $ x = n\pi + \dfrac{{5\pi }}{6} $ where $ n $ is integer.
Hence, the general solution of the equation $ \cot x = - \sqrt 3 $ is $ x = n\pi + \dfrac{{5\pi }}{6} $ where $ n $ is integer.
Note: The solutions of a trigonometric equation for which $ 0 \leqslant x \leqslant 2\pi $ are called principal solutions. The mathematical expression involving integer $ n $ which gives all solutions of a trigonometric equation is called the general solution. In this type of problem, we must remember the values of trigonometric functions for particular angles. Also we must remember some trigonometric identities, results and formulas.
Recently Updated Pages
Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 Physics: Engaging Questions & Answers for Success

Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Business Studies: Engaging Questions & Answers for Success

Trending doubts
Which are the Top 10 Largest Countries of the World?

What are the major means of transport Explain each class 12 social science CBSE

Draw a labelled sketch of the human eye class 12 physics CBSE

Why cannot DNA pass through cell membranes class 12 biology CBSE

Differentiate between insitu conservation and exsitu class 12 biology CBSE

Draw a neat and well labeled diagram of TS of ovary class 12 biology CBSE

