Find out the quadrant of the point which divides internally the line segment joining (3, 4) and (7,-6) in two parts where one part is twice longer than the other.\[\]
(a)\[\text{I}\]
(b) \[\text{II}\]
(c) \[\text{III}\]
(d) \[\text{IV}\]
Answer
610.5k+ views
Hint: A point can divide the line segment either internally or externally. If the point is on the line segment then the point divides the line segment internally at any particular ratio. The line is going to cut the line segment only internally, we only need to take care of the internal case using the section formula.
Complete step-by-step solution:
We know from section formula that if any point $P(x,y)$ which divides a line segment internally $\overline{AB}$ in a ratio $AP:PB=m:n$ with endpoints $A({{x}_{1}},{{y}_{2}})\text{ and B(}{{\text{x}}_{2}}\text{,}{{\text{y}}_{2}}\text{)}$ then the coordinates of P are given by
\[\begin{align}
& x=\dfrac{m{{x}_{2}}+n{{x}_{1}}}{m+n} \\
& y=\dfrac{m{{y}_{2}}+n{{y}_{1}}}{m+n} \\
\end{align}\]
Let us assume that the line divides the line segment internally at the point $P$. Here the coordinates of endpoints $A$ and $B$ are given as $\left( 3,4 \right)$ and (7,-6). According to the question, $P$ can divide the line segment $\overline{AB}$ such that one part is twice the other. We can see it raises two cases.
Case 1:
If the line divides in ratio $2:1$ or AP is twice PB, then $m:n=2:1$. Then the co-ordinates of P are
\[\begin{align}
& x=\dfrac{m{{x}_{2}}+n{{x}_{1}}}{m+n}=\dfrac{2(7)+1(3)}{2+1}=\dfrac{17}{3} \\
& y=\dfrac{m{{y}_{2}}+n{{y}_{1}}}{m+n}=\dfrac{2(-6)+1(4)}{2+1}=-\dfrac{8}{3} \\
\end{align}\]
As $x$ is positive and $y$ is negative, P lies in fourth(IV) quadrant. \[\]
Case 2:
If the line divides in ratio 1:2 or PB is twice AP , then $m:n=1:2$. Hence the co-ordinates of P are
\[\begin{align}
& x=\dfrac{m{{x}_{2}}+n{{x}_{1}}}{m+n}=\dfrac{1(7)+2(3)}{2+1}=\dfrac{13}{3} \\
& y=\dfrac{m{{y}_{2}}+n{{y}_{1}}}{m+n}=\dfrac{1(-6)+2(4)}{2+1}=\dfrac{2}{3} \\
\end{align}\]
As both $x\text{ and }y$ are positive, P lies in first (I) quadrant. The correct choices are A(I) and D(IV).
We can observe from the above image the two possible positions in two different quadrants of P in the $xy-$ plane.
Note: We need to be careful to choose sectional formula from the confusion of internal and external division of a line segment. As the question is ambiguous about the ratio of division, it makes two cases. It more than one option correct type of MCQ.
Complete step-by-step solution:
We know from section formula that if any point $P(x,y)$ which divides a line segment internally $\overline{AB}$ in a ratio $AP:PB=m:n$ with endpoints $A({{x}_{1}},{{y}_{2}})\text{ and B(}{{\text{x}}_{2}}\text{,}{{\text{y}}_{2}}\text{)}$ then the coordinates of P are given by
\[\begin{align}
& x=\dfrac{m{{x}_{2}}+n{{x}_{1}}}{m+n} \\
& y=\dfrac{m{{y}_{2}}+n{{y}_{1}}}{m+n} \\
\end{align}\]
Let us assume that the line divides the line segment internally at the point $P$. Here the coordinates of endpoints $A$ and $B$ are given as $\left( 3,4 \right)$ and (7,-6). According to the question, $P$ can divide the line segment $\overline{AB}$ such that one part is twice the other. We can see it raises two cases.
Case 1:
If the line divides in ratio $2:1$ or AP is twice PB, then $m:n=2:1$. Then the co-ordinates of P are
\[\begin{align}
& x=\dfrac{m{{x}_{2}}+n{{x}_{1}}}{m+n}=\dfrac{2(7)+1(3)}{2+1}=\dfrac{17}{3} \\
& y=\dfrac{m{{y}_{2}}+n{{y}_{1}}}{m+n}=\dfrac{2(-6)+1(4)}{2+1}=-\dfrac{8}{3} \\
\end{align}\]
As $x$ is positive and $y$ is negative, P lies in fourth(IV) quadrant. \[\]
Case 2:
If the line divides in ratio 1:2 or PB is twice AP , then $m:n=1:2$. Hence the co-ordinates of P are
\[\begin{align}
& x=\dfrac{m{{x}_{2}}+n{{x}_{1}}}{m+n}=\dfrac{1(7)+2(3)}{2+1}=\dfrac{13}{3} \\
& y=\dfrac{m{{y}_{2}}+n{{y}_{1}}}{m+n}=\dfrac{1(-6)+2(4)}{2+1}=\dfrac{2}{3} \\
\end{align}\]
As both $x\text{ and }y$ are positive, P lies in first (I) quadrant. The correct choices are A(I) and D(IV).
We can observe from the above image the two possible positions in two different quadrants of P in the $xy-$ plane.
Note: We need to be careful to choose sectional formula from the confusion of internal and external division of a line segment. As the question is ambiguous about the ratio of division, it makes two cases. It more than one option correct type of MCQ.
Recently Updated Pages
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred

Master Class 10 Social Science: Engaging Questions & Answers for Success

Master Class 10 Science: Engaging Questions & Answers for Success

Master Class 10 Maths: Engaging Questions & Answers for Success

Master Class 10 General Knowledge: Engaging Questions & Answers for Success

Master Class 10 Computer Science: Engaging Questions & Answers for Success

Trending doubts
Explain the Treaty of Vienna of 1815 class 10 social science CBSE

In cricket, what is the term for a bowler taking five wickets in an innings?

Who Won 36 Oscar Awards? Record Holder Revealed

What is the median of the first 10 natural numbers class 10 maths CBSE

Why is it 530 pm in india when it is 1200 afternoon class 10 social science CBSE

What is deficiency disease class 10 biology CBSE

