
Find an explicit formula (in terms of $n \in N$ ) for $f(n) = \left( {n - 1} \right) + 2n - 1$.
Answer
585.6k+ views
Hint:
The explicit form of a function is just the simplified form of a given function. Here the function is $f(n) = n - 1 + 2n - 1$. Simplifying this we get the explicit form of the function.
Complete step by step solution:
The explicit formula is nothing other than a mathematical expression with a finite number of well known functions.
In other words the explicit form is nothing other than the simplified form of a given function
Here the function given is $f(n) = \left( {n - 1} \right) + 2n - 1$
In order to find the explicit form we get
$
\Rightarrow f(n) = \left( {n - 1} \right) + 2n - 1 \\
\Rightarrow f(n) = n - 1 + 2n - 1 \\
\Rightarrow f(n) = n + 2n - 1 - 1 \\
\Rightarrow f(n) = 3n - 2 \\
$
Therefore we obtained the explicit form of the given function .
Note:
Explicit means exact or definite. The formula is explicit because as long as it's applied correctly, the nth term can be determined. Arithmetic and geometric sequences have different explicit formulas.
The explicit form of a function is just the simplified form of a given function. Here the function is $f(n) = n - 1 + 2n - 1$. Simplifying this we get the explicit form of the function.
Complete step by step solution:
The explicit formula is nothing other than a mathematical expression with a finite number of well known functions.
In other words the explicit form is nothing other than the simplified form of a given function
Here the function given is $f(n) = \left( {n - 1} \right) + 2n - 1$
In order to find the explicit form we get
$
\Rightarrow f(n) = \left( {n - 1} \right) + 2n - 1 \\
\Rightarrow f(n) = n - 1 + 2n - 1 \\
\Rightarrow f(n) = n + 2n - 1 - 1 \\
\Rightarrow f(n) = 3n - 2 \\
$
Therefore we obtained the explicit form of the given function .
Note:
Explicit means exact or definite. The formula is explicit because as long as it's applied correctly, the nth term can be determined. Arithmetic and geometric sequences have different explicit formulas.
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