
Eye is most sensitive to $5500\overset{o}{\mathop{A}}\,$ and the diameter of the pupil is about 2 mm. Find the angular limit of the resolution of the eye.
Answer
582.9k+ views
Hint: We are given the wavelength of light to which the human eye is most sensitive and the diameter of the pupil. We are asked to find the angular limit of the resolution of the eye. We have an equation to find the angular limit of the resolution of the eye. By substituting the given values in the known equation we will get the required solution.
Formula used:
${{D}_{\theta }}=\dfrac{1.22\lambda }{d}$
Complete step-by-step solution
In the question, it is said that the human eye is most sensitive to light with wavelength $5500\overset{o}{\mathop{A}}\,$. We are also given the diameter of the pupil as 2 mm.
Therefore we gave,
Wavelength, $\lambda =5500\overset{o}{\mathop{A}}\,$
Since this is given in angstrom, we can convert it into meters.
Thus we get,
Wavelength, $\Rightarrow \lambda =5500\times {{10}^{-10}}m$
And the diameter of the pupil,
$d=2mm$
By converting this into meters, we get
$d=2\times {{10}^{-3}}m$
We are asked to calculate the angular limit of the resolution of the eye.
We know that the equation for an angular limit of resolution for the eye is given as,
${{D}_{\theta }}=\dfrac{1.22\lambda }{d}$, were ‘$\lambda $’ is the wavelength and ‘d’ is the diameter
By substituting the values for wavelength and diameter in the above equation, we will get
\[{{D}_{\theta }}=\dfrac{1.22\times 5500\times {{10}^{-10}}}{2\times {{10}^{-3}}}\]
By solving this we will get,
$\Rightarrow {{D}_{\theta }}=3.355\times {{10}^{-4}}rad$
Therefore the angular limit of resolution of eye is $3.355\times {{10}^{-4}}radians$.
Note: Angular limit of resolution or resolving power is simply the ability of an eye or an optical instrument to differentiate between two objects or points. The sensitivity of the human eye to light varies over lights with its wavelength 380 – 800 nm. But in normal daylight conditions, the human eye is most sensitive to light of wavelength 555 nm.
Formula used:
${{D}_{\theta }}=\dfrac{1.22\lambda }{d}$
Complete step-by-step solution
In the question, it is said that the human eye is most sensitive to light with wavelength $5500\overset{o}{\mathop{A}}\,$. We are also given the diameter of the pupil as 2 mm.
Therefore we gave,
Wavelength, $\lambda =5500\overset{o}{\mathop{A}}\,$
Since this is given in angstrom, we can convert it into meters.
Thus we get,
Wavelength, $\Rightarrow \lambda =5500\times {{10}^{-10}}m$
And the diameter of the pupil,
$d=2mm$
By converting this into meters, we get
$d=2\times {{10}^{-3}}m$
We are asked to calculate the angular limit of the resolution of the eye.
We know that the equation for an angular limit of resolution for the eye is given as,
${{D}_{\theta }}=\dfrac{1.22\lambda }{d}$, were ‘$\lambda $’ is the wavelength and ‘d’ is the diameter
By substituting the values for wavelength and diameter in the above equation, we will get
\[{{D}_{\theta }}=\dfrac{1.22\times 5500\times {{10}^{-10}}}{2\times {{10}^{-3}}}\]
By solving this we will get,
$\Rightarrow {{D}_{\theta }}=3.355\times {{10}^{-4}}rad$
Therefore the angular limit of resolution of eye is $3.355\times {{10}^{-4}}radians$.
Note: Angular limit of resolution or resolving power is simply the ability of an eye or an optical instrument to differentiate between two objects or points. The sensitivity of the human eye to light varies over lights with its wavelength 380 – 800 nm. But in normal daylight conditions, the human eye is most sensitive to light of wavelength 555 nm.
Recently Updated Pages
Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 Physics: Engaging Questions & Answers for Success

Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Business Studies: Engaging Questions & Answers for Success

Trending doubts
Which are the Top 10 Largest Countries of the World?

What are the major means of transport Explain each class 12 social science CBSE

Draw a labelled sketch of the human eye class 12 physics CBSE

Why cannot DNA pass through cell membranes class 12 biology CBSE

Differentiate between insitu conservation and exsitu class 12 biology CBSE

Draw a neat and well labeled diagram of TS of ovary class 12 biology CBSE

