
Explain: methanol is more soluble in water than propan-1-ol.
Answer
574.2k+ views
Hint: Methanol is alcohol containing 1 methyl group along with \[1{\text{ }}OH\] group whereas propan-1-ol is compound with a higher number of carbon chains. This information can easily reveal the answer if linked properly to the concept.
Step by step explanation:
In the given question, the concept of solubility is asked in which alcohols solubility is compared and we know alcohol is an organic functional group containing \[OH\] as a group and the rest is a carbon chain.
Now the solubility of this alcohol will depend on a few factors which we will discuss. There is a general rule for solubility which is “Like dissolves like” and here we will see how these alcohols are dissolving in water whereas higher alcohols like propan-1-ol does not get dissolved in water.
Methanol is a compound containing alcohol function with 1 Methyl group. So, it has formula i.e. \[C{H_3}OH\] and when it is dissolved in the solution, there is hydrogen bonding formed between Methanol and water and as a result it becomes soluble in it. In Methanol, the carbon containing part is non-polar in nature whereas \[OH\] is polar in nature.
Becomes soluble due to $(R - {O^{\delta - }} - {H^{\delta + }})$\[and{\text{ }}water{\text{ }}\left( {{\text{ }}{H^{\delta + }} - {O^{\delta - }} - {H^{\delta + }}} \right)\]
So the polar \[OH\] group forms hydrogen bonding with \[{H_2}O\] and therefore, gets dissolved.
Now if we move to alcohol with higher numbers having more carbon chains, they are not soluble in water and it is observed that after 4 chains, they become completely insoluble.
Now this can be explained, in higher alcohols the non-polar group is present large in number compared to polar group so water will form bonding with \[OH\] group but less in number because non-polar group is present in larger numbers.
So, this hydrophobic nature overcomes the hydrophilic nature and as a result solubility in water is lost.
Therefore, methanol is soluble in water and propan-1-ol is not because a larger number of carbons, lower will be solubility in water and also larger the molecular mass, lower will be solubility in water.
Note: To answer solubility related answers, just have some knowledge of types of bonding and forces like Vander-Waals bonding, hydrogen bonding etc. and structure of organic compounds could easily take to the answer when these concepts are linked.
Step by step explanation:
In the given question, the concept of solubility is asked in which alcohols solubility is compared and we know alcohol is an organic functional group containing \[OH\] as a group and the rest is a carbon chain.
Now the solubility of this alcohol will depend on a few factors which we will discuss. There is a general rule for solubility which is “Like dissolves like” and here we will see how these alcohols are dissolving in water whereas higher alcohols like propan-1-ol does not get dissolved in water.
Methanol is a compound containing alcohol function with 1 Methyl group. So, it has formula i.e. \[C{H_3}OH\] and when it is dissolved in the solution, there is hydrogen bonding formed between Methanol and water and as a result it becomes soluble in it. In Methanol, the carbon containing part is non-polar in nature whereas \[OH\] is polar in nature.
Becomes soluble due to $(R - {O^{\delta - }} - {H^{\delta + }})$\[and{\text{ }}water{\text{ }}\left( {{\text{ }}{H^{\delta + }} - {O^{\delta - }} - {H^{\delta + }}} \right)\]
So the polar \[OH\] group forms hydrogen bonding with \[{H_2}O\] and therefore, gets dissolved.
Now if we move to alcohol with higher numbers having more carbon chains, they are not soluble in water and it is observed that after 4 chains, they become completely insoluble.
Now this can be explained, in higher alcohols the non-polar group is present large in number compared to polar group so water will form bonding with \[OH\] group but less in number because non-polar group is present in larger numbers.
So, this hydrophobic nature overcomes the hydrophilic nature and as a result solubility in water is lost.
Therefore, methanol is soluble in water and propan-1-ol is not because a larger number of carbons, lower will be solubility in water and also larger the molecular mass, lower will be solubility in water.
Note: To answer solubility related answers, just have some knowledge of types of bonding and forces like Vander-Waals bonding, hydrogen bonding etc. and structure of organic compounds could easily take to the answer when these concepts are linked.
Recently Updated Pages
Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Class 11 Question and Answer - Your Ultimate Solutions Guide

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Trending doubts
What is meant by exothermic and endothermic reactions class 11 chemistry CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

What are Quantum numbers Explain the quantum number class 11 chemistry CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

