Question

How do you evaluate $x\left( 5x-4 \right)\left( 2x-3 \right)$ ?

Answer 1

Hint: Here we have been asked to evaluate the expression $x\left( 5x-4 \right)\left( 2x-3 \right)$ . For that we will perform simple basic arithmetic operations like multiplication and adding similar terms. We will first multiply the terms with each other and then add the similar terms.

Complete step by step solution:
Now considering from the expression we have been asked to evaluate the expression $x\left( 5x-4 \right)\left( 2x-3 \right)$ .
For that we will perform simple basic arithmetic operations like multiplication and adding similar terms.
We will first multiply the terms with each other and then add the similar terms.
Now we will multiply $\left( 5x-4 \right)$ with $\left( 2x-3 \right)$ after performing multiplication we will have $\Rightarrow x\left( 5x-4 \right)\left( 2x-3 \right)=x\left( 10{{x}^{2}}-15x-8x+12 \right)$ .
Now we will multiply this expression $x$ with $\left( 10{{x}^{2}}-15x-8x+12 \right)$ after performing that we will have $\Rightarrow x\left( 10{{x}^{2}}-15x-8x+12 \right)=10{{x}^{3}}-15{{x}^{2}}-8{{x}^{2}}+12x$ .
For further simplifying we will add and subtract the similar terms. After doing that we will have $\Rightarrow 10{{x}^{3}}-15{{x}^{2}}-8{{x}^{2}}+12x=10{{x}^{3}}-23{{x}^{2}}+12x$.

Therefore we can conclude that the evaluation of the expression $x\left( 5x-4 \right)\left( 2x-3 \right)$ is $10{{x}^{3}}-23{{x}^{2}}+12x$.

Note: While answering questions of this type we should be sure with our calculations. This is a very simple and easy question and it can be solved in a short span of time. We just need to perform simple basic arithmetic operations like addition, subtraction and multiplication for solving questions of this type. The conclusion should be as simple as it is possible. We can also simplify and evaluate any similar expression like $y\left( y-3 \right)\left( y-2 \right)$ we will simplify this expression by performing simple basic arithmetic operations as follows $\Rightarrow y\left( {{y}^{2}}-2y-3y+6 \right)=y\left( {{y}^{2}}-5y+6 \right)\Rightarrow {{y}^{3}}-5{{y}^{2}}+6y$.