# Evaluate: \[(c + 5)(c - 3)\].

Answer

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**Hint:**It is a simple algebraic expression. we can solve this either by directly using the algebraic formula \[(a + b)(a - c) = {a^2} + a(b - c) - bc\] to obtain the final expression or we can simplify the given expression by multiplying the terms to get the required expression.

**Complete step by step answer:**

Given: \[(c + 5)(c - 3)\]

It can be written as

\[c(c - 3) + 5(c - 3)\]

By further calculation

\[{c^2} - 3c + 5c - 15\]

on simplification

\[{c^2} + 2c - 15\]

Further if you simplify the obtained expression by taking the common factor, we will get back the given expression that the obtained solution is \[{c^2} + 2c - 15\]. Simplifying the above using factorization method we get factors as \[5\] and \[ - 3\] with this above expression can be written as \[{c^2} + 5c - 3c - 15\]. Taking common factor and rearranging

\[c(c + 5) - 3(c + 5)\]

Again, taking common factor we get

\[(c + 5)(c - 3)\]

**Note:**the given expression is of the form \[(a + b)(a - b)\]so we can directly use the formula

\[(a + b)(a - c) = {a^2} + a(b - c) - bc\]

Where \[a = c,b = 5,c = 3\]

on substitution in the above formula we get,

\[(c + 5)(c - 3) = {c^2} + c(5 - 3) - (5)(3)\]

\[\Rightarrow {c^2} + 5c - 3c - 15\]

\[\Rightarrow c(c + 5) - 3(c + 5)\]

Further if you simplify the obtained expression by taking the common factor, we will get back the given expression that the obtained solution is \[{c^2} + 2c - 15\]. Simplifying the above using factorization method we get factors as \[5\] and \[ - 3\] with this above expression can be written as \[{c^2} + 5c - 3c - 15\]. (taking common factor and rearranging)

\[ c(c + 5) - 3(c + 5)\]

Again, taking common factor we get,

\[(c + 5)(c - 3)\]

The solution is the same in both cases. In the above problem we cannot simplify the equation further to get the value of c because the given expression is not equated to zero. (that is supposed if the given equation is of the form \[(c + 5)(c - 3) = 0\] then we can simplify it by using Factorization method or formula method).

Last updated date: 26th Sep 2023

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