Question

Ethylene is a member of
A. Alkyne
B. Olefin
C. Paraffin
D. Amine

Answer 1

Hint: As per IUPAC, the word root is eth which indicates that the compound contains two carbons and ‘ene’ which is a primary suffix indicates that the compound is unsaturated (double bond between both carbons). Ethylene is also named ethene which is a compound of the alkene class (hydrocarbons containing a double bond between carbons).

Complete Step by Step Answer:
As we discussed in the hint that ethylene or ethylene is a double-bonded unsaturated compound classified into the alkane class. The general formula of an alkane is \[{{C}_{2}}{{H}_{2n}}\] where n is the number of carbon. In ethene, there are two carbons so the number of hydrogen will be four\[{{C}_{2}}{{H}_{4}}\]. As there are four hydrogens instead of six (as in alkane) there is a double bond between both carbon atoms which makes it an unsaturated compound (pi bonding between two carbons of ethane).

Now in the first option alkyl is given but ethylene cannot be alkyne as this is a part of alkene hydrocarbons (containing double bonds) whereas in alkyne there is a triple bond between two carbons (
\[{{C}_{n}}{{H}_{2n-2}}\]where n should be created then 1).

Also, ethylene cannot be a part of paraffin as paraffin is a class of alkane (unsaturated compound), hydrocarbon containing all single bonds, and also very unreactive (paraffin word meaning is unreactive or very less relative). Also, it cannot be amine because amine is a nitrogen-based compound in which nitrogen is bonded with carbon or with hydrogen. If we replace one hydrogen in hydrocarbon with nitrogen then the compound is known as amine.

But Olefins are double-bonded hydrocarbons or can be classified in the alkene hydrocarbons. So ethylene or ethylene is a member of olefins which is a double bonded compound (man-made fibres).
Thus, the correct option is B.

Note: The ethylene or ethylene is a compound in which two carbon atoms are double bonded means both carbon's px orbital is showing sidewise overlapping forming one pi bond with each other and both carbon py orbital forming head-on overlapping results in one sigma bond. So, one pi and one sigma bond between both carbons of ethane give rise to a double bond (both carbon in ethane is in \[s{{p}^{2}}\] hybridization as there are three sigma bonds present).