Question

Ethanol reacts with sodium and forms two products. These are:
A. Sodium ethanoate and hydrogen
B. Sodium ethanoate and oxygen
C. Sodium ethoxide and hydrogen
D. Sodium ethoxide and water

Answer 1

Hint- In order to deal with this question first we will introduce the term ethanol and sodium further then we will write the reaction of sodium and ethanol and according to it we will get the required answer.

Complete step-by-step answer:
Ethanol: Ethanol (also known as ethyl alcohol, plant alcohol, alcohol, or merely alcohol) is an organic compound, a clear alcohol with the chemical formula ${C_2}{H_6}O$ . Its formula can be also written as ${C_2}{H_5}OH$ an ethyl group linked to a hydroxyl group), and is often abbreviated as $Et - OH$.
Sodium: Sodium is a chemical element with the symbol $Na$ ("natrium" from Latin) and the atomic number 11. It is a highly reactive, silvery-white alloy. Sodium is an alkali metal and is in the periodic table of group 1. It's only stable isotope is ${}^{23}Na$.
The equation for the reaction between sodium and ethanol can be written as:
$2C{H_3}C{H_2}OH + 2Na \to 2C{H_3}C{H_2}ONa + {H_2}$
Therefore, the products formed in the reaction are hydrogen and sodium ethoxide.
Sodium ethoxide is colorless in nature.
Hydrogen gas evolves as bubbles in this reaction.
It is an acid base reaction.
This reaction helps to show the acidic nature of ethanol.
Hence, sodium ethoxide and hydrogen are formed when ethanol reacts with sodium.
So, the correct answer is option C.

Note- Ethanol is a solvent that is toxic, flammable, colorless and has a faint odour. It is a psychoactive drug, which is the primary active ingredient in alcoholic beverages. Sodium-free metal does not exist in nature because it is very reactive, so compounds must be prepared.