
What is the equivalent weight of ${{\text{H}}_{\text{2}}}\text{S}{{\text{O}}_{\text{4}}}$ in the reaction?
\[{{\text{H}}_{\text{2}}}\text{S}{{\text{O}}_{\text{4}}}\text{ + NaI }\to \text{ N}{{\text{a}}_{\text{2}}}\text{S}{{\text{O}}_{\text{4}}}\text{ + }{{\text{I}}_{\text{2}}}\text{ + }{{\text{H}}_{\text{2}}}\text{S + }{{\text{H}}_{\text{2}}}\text{O}\]
(A) 12.25
(B) 49
(C) 61.25
(D) None of these
Answer
508.8k+ views
Hint: Molar mass is the total mass of atoms present in 1 mole of the element. Similarly, equivalent weight is the mass of one equivalent of the molecule or atom. For calculations, equivalent weight is the ratio of molecular mass and n-factor of one mole of molecules/atoms.
Complete step by step answer:
Equivalent weight also known as gram equivalent is the mass of one equivalent, that is the mass of a given substance which will combine or displace a fixed quantity of another substance in the reaction.
The equivalent weight of an element is the mass which combines with 1 gram of hydrogen or 8.0 grams of oxygen or 35.5 grams of chlorine at STP. These values correspond to the atomic weight of the molecule divided by the usual valence shown by the atom present in the molecule.
We will now calculate the equivalent weight of ${{\text{H}}_{\text{2}}}\text{S}{{\text{O}}_{\text{4}}}$ in the reaction given above.
\[{{\text{H}}_{\text{2}}}\text{S}{{\text{O}}_{\text{4}}}\text{ + NaI }\to \text{ N}{{\text{a}}_{\text{2}}}\text{S}{{\text{O}}_{\text{4}}}\text{ + }{{\text{I}}_{\text{2}}}\text{ + }{{\text{H}}_{\text{2}}}\text{S + }{{\text{H}}_{\text{2}}}\text{O}\]
In the above reaction we see that there is a transfer of 8 electrons when the sulphur atom in sulphuric acid changes its oxidation state from +6 to -2. Hence the n-factor becomes 8.
Equivalent weight = $\dfrac{\text{Molar mass}}{\text{n-factor}}$
Equivalent weight = $\dfrac{\text{98}}{8}$ = 12.25 g
So, the correct answer is “Option A”.
Note: In case of acid-base neutralization reactions, the equivalent weight of an acid or base is the mass which provides or reacts with 1 mole of positive hydrogen ions.
Complete step by step answer:
Equivalent weight also known as gram equivalent is the mass of one equivalent, that is the mass of a given substance which will combine or displace a fixed quantity of another substance in the reaction.
The equivalent weight of an element is the mass which combines with 1 gram of hydrogen or 8.0 grams of oxygen or 35.5 grams of chlorine at STP. These values correspond to the atomic weight of the molecule divided by the usual valence shown by the atom present in the molecule.
We will now calculate the equivalent weight of ${{\text{H}}_{\text{2}}}\text{S}{{\text{O}}_{\text{4}}}$ in the reaction given above.
\[{{\text{H}}_{\text{2}}}\text{S}{{\text{O}}_{\text{4}}}\text{ + NaI }\to \text{ N}{{\text{a}}_{\text{2}}}\text{S}{{\text{O}}_{\text{4}}}\text{ + }{{\text{I}}_{\text{2}}}\text{ + }{{\text{H}}_{\text{2}}}\text{S + }{{\text{H}}_{\text{2}}}\text{O}\]
In the above reaction we see that there is a transfer of 8 electrons when the sulphur atom in sulphuric acid changes its oxidation state from +6 to -2. Hence the n-factor becomes 8.
Equivalent weight = $\dfrac{\text{Molar mass}}{\text{n-factor}}$
Equivalent weight = $\dfrac{\text{98}}{8}$ = 12.25 g
So, the correct answer is “Option A”.
Note: In case of acid-base neutralization reactions, the equivalent weight of an acid or base is the mass which provides or reacts with 1 mole of positive hydrogen ions.
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