Question

During glycolysis, the conversion of one mole of 3P GAld to ${C_3}{H_4}{O_3}$ yields 2 moles of ATP. But the oxidation of glucose to ${C_3}{H_4}{O_3}$ produces a total of 4 moles of ATP.

Where do the remaining 2 moles of ATP come from?

A. One mole of glucose gives 2 moles of 3P GAld

B. Glycolysis produce 2NADH

C. Fermentation of ${C_3}{H_4}{O_3}$ produces 2 ATP more

D. 2 ATP are used in the conversion of glucose to 3P GAld

Answer 1

Hint: Glycolysis is that the method by that one molecule of aldohexose is reborn into 2 molecules of pyruvate, 2 gas ions and 2 molecules of water. Through this method, the 'high energy' molecules of nucleotide and NADH are synthesised. The pyruvate molecules then proceed to the link reaction, wherever acetyl-coA is made.

Complete answer:

Glycolysis, which accurately means "breakdown of sugar," could be a catabolic method during which six-carbon sugars (hexoses) are unit modified and countered into pyruvate molecules. The corresponding anabolic pathway by which aldohexose is synthesized is termed gluconeogenesis. Each metastasis and gluconeogenesis aren't major oxidative/reductive processes by themselves, with one step in each involving loss/gain of electrons, however, the merchandise of metastasis, pyruvate, will be utterly modified to \[C{O_2}\].

 Indeed, while not production of pyruvate from aldohexose in metastasis, a significant energy supply for the cell isn't out there. Against this, gluconeogenesis will synthesize aldohexose reductively from terribly easy materials, like pyruvate and acetyl-CoA/ glyoxylate (at least in plants). For these reasons, we tend to embrace these pathways within the red/ox assortment. Two moles of nucleotide are created once one mole of glyceric aldehyde three phosphates or 3PGA is born-again to acid. glyceric aldehyde three phosphates are created from aldohexose within the initial part of metastasis. every mole of aldohexose produces two moles of glyceric aldehyde three phosphates, therefore, 2 moles of 3P GA once born-again to acid, yield four moles of nucleotide.

So, the right answer is 'One mole of aldohexose provides two moles of three P GAld.

Hence option (A) is the correct answer. 

Note:

The overall reaction of glycolysis which occurs in the cytoplasm is represented generally as below,

Glucose + 2NAD⁺  2 Pi + 2 ADP = 2 pyruvate + 2 ATP + 2 NADH +2 H₂O

The major steps of glycolysis are defined in the graphic on the left. There are a variety of starting points for glycolysis; although, the most usual ones start with glucose or glycogen to produce glucose-6-phosphate, containing phosphate groups at 6th no of carbon. The starting points for other monosaccharides, galactose and fructose have eventually occurred.