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Draw rough sketches for $ \Delta XYZ $ such that YL is an altitude in the exterior of the triangle.

Answer
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Hint: We can draw an altitude in the exterior of a triangle only if it is an obtuse angled triangle.By using this concept we draw the triangle first and then altitude to

Complete step-by-step answer:
We have to draw an altitude in the exterior of the $ \Delta XYZ $
An altitude can be drawn in the exterior of a triangle only if it is an obtuse angled triangle.
So, we need to draw $ \Delta XYZ $ as an obtuse angled triangle as shown in the figure.
seo images

Altitude (perpendicular line).
 $ YL = $ exterior altitude of $ \Delta XYZ $ .
Here,
In figure, $ \Delta XYZ $ is obtuse angled triangle because we can only draw an exterior altitude from abuse angle it can observed that on $ \Delta XYZ,YZ $ is an altitude drawn interior to side $ XZ $ which is extends up to point $ L. $

Note: To know whether the altitude will be on the exterior of a triangle or in the interior of a triangle, we need to know the properties of the triangle.
For an acute angled triangle, the altitude will be in the interior of a triangle.
For a right angled triangle, the altitude will be at the angle which is right angled.
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