
Draw an angle to measure \[147^\circ \] and find its bisector.
Answer
566.7k+ views
Hint: In the given question, we need to first draw an angle of the given measure, which is\[147^\circ \]. Clearly, this angle is an obtuse angle as it is greater than \[90^\circ \]. Then we need to follow some basic geometric steps to calculate and construct the bisector of the given angle using a scale, a pencil and a compass, i.e., without the help of a protractor.
Complete step-by-step answer:
In the given question, the required angle which is to be drawn is of measure \[147^\circ \]. Since this angle is not a multiple of \[15\], it cannot be drawn with just a scale, a pencil and a compass. So, we are going to have to use a protractor for drawing this angle.
So first, we draw a ray OA
Then, we place a protractor on the point O and mark a point B on the \[147^\circ \] marking on the protractor and join OB. Thus, \[\angle AOB = 147^\circ \]
Now, we have to construct the bisector of \[\angle AOB\].
For that, we mark points C and D on the corners of the angle as shown.
Now, taking C and D as centers and radius more than \[\frac{1}{2}{\rm{CD}}\], draw arcs to intersect each other.
Let the intersecting point be E.
Join O and E. And we have our bisector.
Thus, OE is the bisector of \[\angle AOB\].
Note: So, for solving questions of such type, we first write what has been given to us. Then we write down what we have to find. Then we think about the formulae which contains the known and the unknown and pick the one which is the most suitable for the answer. Then we put in the knowns into the formula, evaluate the answer and find the unknown. It is really important to follow all the steps of the formula to solve the given expression very carefully and in the correct order, because even a slightest error is going to make the whole expression wrong and is going to give us an incorrect answer.
Complete step-by-step answer:
In the given question, the required angle which is to be drawn is of measure \[147^\circ \]. Since this angle is not a multiple of \[15\], it cannot be drawn with just a scale, a pencil and a compass. So, we are going to have to use a protractor for drawing this angle.
So first, we draw a ray OA
Then, we place a protractor on the point O and mark a point B on the \[147^\circ \] marking on the protractor and join OB. Thus, \[\angle AOB = 147^\circ \]
Now, we have to construct the bisector of \[\angle AOB\].
For that, we mark points C and D on the corners of the angle as shown.
Now, taking C and D as centers and radius more than \[\frac{1}{2}{\rm{CD}}\], draw arcs to intersect each other.
Let the intersecting point be E.
Join O and E. And we have our bisector.
Thus, OE is the bisector of \[\angle AOB\].
Note: So, for solving questions of such type, we first write what has been given to us. Then we write down what we have to find. Then we think about the formulae which contains the known and the unknown and pick the one which is the most suitable for the answer. Then we put in the knowns into the formula, evaluate the answer and find the unknown. It is really important to follow all the steps of the formula to solve the given expression very carefully and in the correct order, because even a slightest error is going to make the whole expression wrong and is going to give us an incorrect answer.
Recently Updated Pages
Master Class 8 Social Science: Engaging Questions & Answers for Success

Master Class 8 English: Engaging Questions & Answers for Success

Class 8 Question and Answer - Your Ultimate Solutions Guide

Master Class 8 Maths: Engaging Questions & Answers for Success

Master Class 8 Science: Engaging Questions & Answers for Success

Master Class 7 English: Engaging Questions & Answers for Success

Trending doubts
What is BLO What is the full form of BLO class 8 social science CBSE

Citizens of India can vote at the age of A 18 years class 8 social science CBSE

Full form of STD, ISD and PCO

Advantages and disadvantages of science

Right to vote is a AFundamental Right BFundamental class 8 social science CBSE

What are the 12 elements of nature class 8 chemistry CBSE

