Draw a line segment of length 7.6 cm and construct its perpendicular bisector.
Hint: In this question, we will first draw a line segment of given length and then construct arcs from its two end points and join the point of intersection of arcs to draw its perpendicular bisector.
Complete step-by-step answer:
Firstly, let us draw a line segment AB of length 7.6 cm with ruler scale.
Now, let us take a compass and open it to a radius which is more than half of the length of the line segment and less than full length of line segment. Let us now place the compass at point A and draw an arc above the line segment.
Now, without changing the radius of the compass, we will draw an arc from point A again, below the line segment.
We will now repeat the same with point B. Without changing the radius of the compass, let us now place it at point B and draw an arc above the line segment.
Now, with the same radius of the compass, we will draw an arc from point B again, below the line segment.
We will mark the points of intersection of arcs above the line segment and below the line segment as R and S.
Now, we will draw a straight line passing through points R and S and mark it UT.
Hence, UT is a perpendicular bisector of line segment AB of length 7.6 cm.
Note: While drawing arcs, check that the tip of the compass does not move from points A or B. Also, once you have taken the radius of the compass to draw an arc, do not change it in the whole construction procedure.