
Draw a graph of $\lambda mV/s\sqrt C $ for acetic acid (weak electrolyte) solution.
Answer
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Hint:We have to remember that the conducting power of all the ions made by dissolving one mole of an electrolyte in a solution is known as molar conductivity. Kohlraush’s law could be described as the equivalent conductivity of an electrolyte at infinite dilution is equal to total conductance of the anions and cations present. Molar conductivity is expressed in terms of Siemens metre-squared per mole $\left( {S{m^2}mo{l^{ - 1}}} \right)$.
Complete step by step answer:
-We know that molar conductivity of a solution comprises one mole of the electrolyte and it is not fixed. It is the conductance unit mole of electrolyte that is kept between two electrodes of unit cross section or at a distance of one-centimeter.
-We must remember that the molar conductivity of a strong electrolyte like strong bases and strong acids at infinite dilution could be determined by extrapolation as a straight line plot is obtained. In the case of weak electrolyte, we cannot measure the molar conductivity at infinite solution experimentally and also by extrapolation because the plot determined is not straight line, the highest value of molar conductivity at infinite solution cannot be obtained.
-The dissociation of weak electrolyte keeps increasing with respect to dilution. When the solution is more dilute the value of molar conductivity of greater and ionic dissociation also increases.
-An example of weak electrolyte is acetic acid. The molar conductivity of acetic acid is high in dilute solutions of acetic acid when compared to concentrated solutions of acetic acid.
-A graph containing $\lambda mV/s\sqrt C $ for acetic acid (weak electrolyte) solution is drawn below,
Note:
As we know that the Kohlraush’s law is useful in obtaining the limiting molar conductivity of any electrolytes. Lower molar conductivities and lower degree of dissociation for higher concentration are exhibited by weaker electrolytes. It is used to calculate the dissolution of salts that are partially soluble.
Complete step by step answer:
-We know that molar conductivity of a solution comprises one mole of the electrolyte and it is not fixed. It is the conductance unit mole of electrolyte that is kept between two electrodes of unit cross section or at a distance of one-centimeter.
-We must remember that the molar conductivity of a strong electrolyte like strong bases and strong acids at infinite dilution could be determined by extrapolation as a straight line plot is obtained. In the case of weak electrolyte, we cannot measure the molar conductivity at infinite solution experimentally and also by extrapolation because the plot determined is not straight line, the highest value of molar conductivity at infinite solution cannot be obtained.
-The dissociation of weak electrolyte keeps increasing with respect to dilution. When the solution is more dilute the value of molar conductivity of greater and ionic dissociation also increases.
-An example of weak electrolyte is acetic acid. The molar conductivity of acetic acid is high in dilute solutions of acetic acid when compared to concentrated solutions of acetic acid.
-A graph containing $\lambda mV/s\sqrt C $ for acetic acid (weak electrolyte) solution is drawn below,
Note:
As we know that the Kohlraush’s law is useful in obtaining the limiting molar conductivity of any electrolytes. Lower molar conductivities and lower degree of dissociation for higher concentration are exhibited by weaker electrolytes. It is used to calculate the dissolution of salts that are partially soluble.
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