
How does molecular weight affect the rate of diffusion?
Answer
541.5k+ views
Hint: 1)Substances diffuse as per their concentration gradient; inside a system, various substances in the medium will each diffuse at various rates as per their individual gradients.
2)After a substance has diffused absolutely through space, taking out its concentration gradient, molecules will in any case move around in the space, yet there will be no net movement of the number of molecules starting with one territory then onto the next, a state known as dynamic equilibrium.
3)A few factors influence the rate of diffusion of a solute including the mass of the solute, the temperature of the climate, the solvent density, and the distance traveled
Complete step by step answer:
Diffusion is the development of particles from where they are more concentrated to where they are less concentrated.
The average kinetic energy of a molecule (KE) gives us the temperature of a substance
\[KE\] = $\dfrac{{1m{v^2}}}{2}$
On the off chance that we have two gases (An and B) with gas A being heavier than B. The Kinetic energy of the two gases will be the equivalent if the gases are at a similar temperature.
\[K{E_A} = K{E_B}\]
So at equivalent temperatures, a lighter molecule (B) should have a greater velocity (speed) and a heavier molecule (A) must have a lower speed.
$\dfrac{{1{m_A}{\text{.}}{v_A}^2}}{2}$ =$\dfrac{{1{m_B}{\text{.}}{V_B}^2}}{2}$
Note:
The extent of the concentration gradient: The more prominent the distinction in concentration, the more rapid the diffusion. The closer the distribution of the material gets to equilibrium, the slower the pace of diffusion becomes.
Mass of the Molecules diffusing: Heavier atoms move all the more gradually; hence, they diffuse all the more gradually. The opposite is valid for lighter atoms.
Temperature: Higher temperatures increment the energy and in this way, the movement of the atoms, increasing the rate of diffusion
2)After a substance has diffused absolutely through space, taking out its concentration gradient, molecules will in any case move around in the space, yet there will be no net movement of the number of molecules starting with one territory then onto the next, a state known as dynamic equilibrium.
3)A few factors influence the rate of diffusion of a solute including the mass of the solute, the temperature of the climate, the solvent density, and the distance traveled
Complete step by step answer:
Diffusion is the development of particles from where they are more concentrated to where they are less concentrated.
The average kinetic energy of a molecule (KE) gives us the temperature of a substance
\[KE\] = $\dfrac{{1m{v^2}}}{2}$
On the off chance that we have two gases (An and B) with gas A being heavier than B. The Kinetic energy of the two gases will be the equivalent if the gases are at a similar temperature.
\[K{E_A} = K{E_B}\]
So at equivalent temperatures, a lighter molecule (B) should have a greater velocity (speed) and a heavier molecule (A) must have a lower speed.
$\dfrac{{1{m_A}{\text{.}}{v_A}^2}}{2}$ =$\dfrac{{1{m_B}{\text{.}}{V_B}^2}}{2}$
Note:
The extent of the concentration gradient: The more prominent the distinction in concentration, the more rapid the diffusion. The closer the distribution of the material gets to equilibrium, the slower the pace of diffusion becomes.
Mass of the Molecules diffusing: Heavier atoms move all the more gradually; hence, they diffuse all the more gradually. The opposite is valid for lighter atoms.
Temperature: Higher temperatures increment the energy and in this way, the movement of the atoms, increasing the rate of diffusion
Recently Updated Pages
Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Class 11 Question and Answer - Your Ultimate Solutions Guide

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Trending doubts
10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

Explain zero factorial class 11 maths CBSE

What is a periderm How does periderm formation take class 11 biology CBSE

