Does electric flux depend on shape?
Answer
561.9k+ views
Hint: Remember the most important concept which you studied in the topic of electrostatics, that is Gauss law, remember the equation of gauss law. According to gauss law electric flux does not depend on the shape of the object.
Complete step by step answer:
The concept of flux describes how much of something goes through a given area. More formally, it is the dot product of a vector field with an area. You can also understand this concept by saying that flux of an electric field is a measure of the number of electric field lines passing through an area. The numerical value of the flux depends on the magnitude of the electrical field and the area, as well as the relative orientation of the area with respect to the direction of the electric field.
Gauss Law -
${\Phi _{\text{E}}}\, = \,\dfrac{{\text{Q}}}{{{\varepsilon _0}}}\,........(Gauss\,Law)$
Here ${\Phi _{\text{E}}}$ is electrical flux,
${\text{Q}}$ is charge enclosed and
${\varepsilon _0}$ is an electric constant.
When we consider this equation, we can find that electric flux is independent of the shape and size of the object of which we are talking about. Electric flux is dependent on the charge enclosed by the surface. It also depends on the magnitude and direction of the electrical field.
Note:
Electric field is an electrical property associated with each point in space when charge is present in any form. Electric field is a vector quantity because of having direction and magnitude both. The electric field lines flow from positive to negative charges. Any charged object is the source of an electric field.
Complete step by step answer:
The concept of flux describes how much of something goes through a given area. More formally, it is the dot product of a vector field with an area. You can also understand this concept by saying that flux of an electric field is a measure of the number of electric field lines passing through an area. The numerical value of the flux depends on the magnitude of the electrical field and the area, as well as the relative orientation of the area with respect to the direction of the electric field.
Gauss Law -
${\Phi _{\text{E}}}\, = \,\dfrac{{\text{Q}}}{{{\varepsilon _0}}}\,........(Gauss\,Law)$
Here ${\Phi _{\text{E}}}$ is electrical flux,
${\text{Q}}$ is charge enclosed and
${\varepsilon _0}$ is an electric constant.
When we consider this equation, we can find that electric flux is independent of the shape and size of the object of which we are talking about. Electric flux is dependent on the charge enclosed by the surface. It also depends on the magnitude and direction of the electrical field.
Note:
Electric field is an electrical property associated with each point in space when charge is present in any form. Electric field is a vector quantity because of having direction and magnitude both. The electric field lines flow from positive to negative charges. Any charged object is the source of an electric field.
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