Question

What does 56 degrees Celsius equal in Fahrenheit?

Answer 1

Hint: Here in this question we have been asked to convert 56 degrees Celsius in Fahrenheit scale for doing that we will use the formula given as $F={\displaystyle \frac{9}{5}}C+32$ that firstly we will multiply the given temperature with ${\displaystyle \frac{9}{5}}$ and then add $32$ to that.

Complete step by step answer:
Now considering the question we have been asked to convert 56 degrees Celsius in Fahrenheit scale.
Celsius and Fahrenheit are two units of temperature and the Celsius temperature scale was initially created to start from zero which was the temperature at which water freezes and the Fahrenheit scale starts from $32{}^{\circ }F$ which is equal to the zero degree Celsius.
The ending point of Celsius temperature is $100$ which is the boiling point of water and for Fahrenheit is $212$ . We know that on the Celsius scale we have 100 equal divisions and the Fahrenheit scale has 180 equal divisions.
From the basic concepts we know that the formula for conversion of Celsius scale to Fahrenheit scale is given as ${\displaystyle \frac{C-0}{100}}={\displaystyle \frac{F-32}{180}}$ which is further simplified as $F={\displaystyle \frac{9}{5}}C+32$.
By using this we can say that $56{}^{\circ }C$ will be given as
$\begin{array}{rl}& {\displaystyle \frac{9}{5}}\left(56\right)+32=9\left(11.2\right)+32\\ & \Rightarrow 100.8+32=132.8\end{array}$.

Therefore we can conclude that the value of 56 degrees Celsius in Fahrenheit scale is given as $132.8$.

Note: This is a basic question and can be easily answered within a short span of time. Someone can make a mistake if they forget the values like considering the formula as $F={\displaystyle \frac{9}{2}}C+32$ then the conclusion will be given as
$\begin{array}{rl}& {\displaystyle \frac{9}{2}}\left(56\right)+32=9\left(28\right)+32\\ & \Rightarrow 252+32=284\end{array}$
which is a wrong answer clearly. Similarly we have different temperature scales serving for different purposes like Kelvin and many more.