Question

What is the distribution of electrons in an oxygen atom?
A) (2, 4)
B) (2, 8)
C) (2, 6)
D) (2, 10)

Answer 1

Hint: We know that Oxygen is the compound component with the symbol $O$ and nuclear number \[8\]. It is an individual from the chalcogen group in the table, an exceptionally responsive nonmetal, and an oxidizing specialist that promptly shapes oxides with most components just as with other compounds.

Complete step by step solution:
We know that the Aufbau’s principle states that electrons are filled into atomic orbitals within the increasing order of orbital energy states. Consistent with the Aufbau principle the available atomic orbitals with rock bottom energy levels are occupied before those with higher energy levels.
Hund’s Rule:
As per this rule each orbital in a subshell is singly occupied with one electron before any one orbital is doubly involved and all electrons in separately involved orbitals have a similar turn.
We know that oxygen is a part of the p-block in the periodic table and the atomic number of Oxygen is $8$. The electronic configuration of oxygen is $1{s^2}2{s^2}2{p^4}$. Thus the electrons are distributed in an oxygen atom as (2, 6).
Therefore, the option C is correct.

Note:We have to remember that the representative elements are the chemical elements within the group-1, group-2 and within the groups from 13 to 18. Representative elements also are referred to as group-A elements or s-block elements and p-block elements or main group elements.
As we know that the S-block elements have their valence electrons within the outermost s-orbitals and are in two types as alkali metals and alkaline-earth metal metals. Alkali metals are group-1 whereas alkali earth metals are group-2 elements.
We have to remember that the P-block elements have their valence electrons within the outermost p-orbitals. Most p-block elements are non-metals including some metalloids.
Most of the compounds formed by representative elements are colorless.