Dimensions of electrical resistances are
\[\begin{align}
& A)\left[ M{{L}^{2}}{{T}^{-3}}{{A}^{-1}} \right] \\
& B)\left[ M{{L}^{2}}{{T}^{-3}}{{A}^{-2}} \right] \\
& C)\left[ M{{L}^{3}}{{T}^{-3}}{{A}^{-2}} \right] \\
& D)\left[ M{{L}^{-1}}{{L}^{3}}{{T}^{3}}{{A}^{2}} \right] \\
\end{align}\]
Answer
642.9k+ views
Hint: If we need to find out which of these is correct, we need to know the dimensional formula for resistance, which is the ratio of electric voltage to the electric current. Then we will compare that dimensional formula with the given dimensional formula and find out which one is correct.
Complete step by step answer:
We must know that the electrical resistance is defined as the ratio of the electric voltage to electric current. i.e.
\[\text{Resistance=}\dfrac{\text{Voltage}}{\text{Current}}=\dfrac{V}{I}\]
But, the voltage here is defined as work done by an electric charge divided by the amount of charge which is expressed as product of current and time. Because current is the rate of change of charge in a unit area of the cross section.
\[\text{Voltage=}\dfrac{\text{Work}}{\text{Charge}}\text{=}\dfrac{\text{Work}}{\text{Current }\!\!\times\!\!\text{ Time}}=\dfrac{W}{I\times t}\]
Substituting this in the equation of resistance, we will get
\[R=\dfrac{W}{{{I}^{2}}\times t}\]
We know, the dimensional formula of work is \[\left[ M{{L}^{2}}{{T}^{-2}} \right]\], dimensional formula of current is \[\left[ A \right]\] and dimensional formula of time is\[\left[ T \right]\]. Let us substitute these dimensional formulas in the equation for resistance.
\[\Rightarrow R=\dfrac{W}{{{I}^{2}}\times t}=\dfrac{\left[ M{{L}^{2}}{{T}^{-2}} \right]}{\left[ {{A}^{2}} \right]\left[ T \right]}\]
\[R=\left[ M{{L}^{2}}{{A}^{-2}}{{T}^{-3}} \right]\]
Therefore, the dimensional formula of resistance is found to be \[\left[ M{{L}^{2}}{{A}^{-2}}{{T}^{-3}} \right]\].
Now, if we compare this with the given options, we can see that option b is the right answer.
Note:
In the solution we are using ohm’s law to determine the expression for resistance. Ohm’s law states that current is directly proportional to the voltage across the conductor. i.e. \[V=IR\]. Here, electrical resistance is a barrier for current having S.I. unit \[\Omega \]. The resistance of a material depends upon the resistivity of the particular material (\[\rho \]), length (\[l\]) and area of cross section (\[A\]). Here, resistance is also expressed as \[R=\dfrac{\rho l}{A}\].
Complete step by step answer:
We must know that the electrical resistance is defined as the ratio of the electric voltage to electric current. i.e.
\[\text{Resistance=}\dfrac{\text{Voltage}}{\text{Current}}=\dfrac{V}{I}\]
But, the voltage here is defined as work done by an electric charge divided by the amount of charge which is expressed as product of current and time. Because current is the rate of change of charge in a unit area of the cross section.
\[\text{Voltage=}\dfrac{\text{Work}}{\text{Charge}}\text{=}\dfrac{\text{Work}}{\text{Current }\!\!\times\!\!\text{ Time}}=\dfrac{W}{I\times t}\]
Substituting this in the equation of resistance, we will get
\[R=\dfrac{W}{{{I}^{2}}\times t}\]
We know, the dimensional formula of work is \[\left[ M{{L}^{2}}{{T}^{-2}} \right]\], dimensional formula of current is \[\left[ A \right]\] and dimensional formula of time is\[\left[ T \right]\]. Let us substitute these dimensional formulas in the equation for resistance.
\[\Rightarrow R=\dfrac{W}{{{I}^{2}}\times t}=\dfrac{\left[ M{{L}^{2}}{{T}^{-2}} \right]}{\left[ {{A}^{2}} \right]\left[ T \right]}\]
\[R=\left[ M{{L}^{2}}{{A}^{-2}}{{T}^{-3}} \right]\]
Therefore, the dimensional formula of resistance is found to be \[\left[ M{{L}^{2}}{{A}^{-2}}{{T}^{-3}} \right]\].
Now, if we compare this with the given options, we can see that option b is the right answer.
Note:
In the solution we are using ohm’s law to determine the expression for resistance. Ohm’s law states that current is directly proportional to the voltage across the conductor. i.e. \[V=IR\]. Here, electrical resistance is a barrier for current having S.I. unit \[\Omega \]. The resistance of a material depends upon the resistivity of the particular material (\[\rho \]), length (\[l\]) and area of cross section (\[A\]). Here, resistance is also expressed as \[R=\dfrac{\rho l}{A}\].
Recently Updated Pages
Basicity of sulphurous acid and sulphuric acid are

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Chemistry: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Trending doubts
Difference Between Prokaryotic Cells and Eukaryotic Cells

Two of the body parts which do not appear in MRI are class 11 biology CBSE

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

10 examples of friction in our daily life

Draw a diagram of nephron and explain its structur class 11 biology CBSE

What will happen if the mucus is not secreted by the class 11 biology CBSE

