Differentiate $\left( {{{\sin }^2}x} \right)$ with respect to $x$.
Answer
526.2k+ views
Hint: In the given problem, we are required to differentiate $\left( {{{\sin }^2}x} \right)$ with respect to x. Since, $\left( {{{\sin }^2}x} \right)$ is a composite function, so we will have to apply chain rule of differentiation in the process of differentiating $\left( {{{\sin }^2}x} \right)$ . So, differentiation of $\left( {{{\sin }^2}x} \right)$ with respect to x will be done layer by layer using the chain rule of differentiation. Also the derivative of $\sin (x)$with respect to $x$ must be remembered.
Complete step by step answer:
So, Derivative of $\left( {{{\sin }^2}x} \right)$ with respect to $x$can be calculated as $\dfrac{d}{{dx}}\left( {{{\sin }^2}x} \right)$ .
Now, $\dfrac{d}{{dx}}\left( {{{\sin }^2}x} \right)$
Taking the power outside the bracket in order to apply chain rule of differentiation.
\[\dfrac{d}{{dx}}\left[ {{{\left( {\sin x} \right)}^2}} \right]\]
Now, Let us assume $u = \sin (x)$. So substituting $\sin (x)$ as $u$, we get,
$\dfrac{d}{{dx}}{\left[ u \right]^2} = 2u\dfrac{{du}}{{dx}}$
Now, putting back $u$ as $\sin (x)$, we get,
$2\sin x\dfrac{{d\left( {\sin x} \right)}}{{dx}}$ because \[\dfrac{{du}}{{dx}} = \dfrac{{d(\sin x)}}{{dx}}\]
Now, we know that the derivative of $\sin x$ with respect to $x$ is \[\cos x\]. So, $\dfrac{d}{{dx}}\left( {\sin x} \right) = \cos x$.
So, Substituting the equivalent expression of $\dfrac{d}{{dx}}\left( {\sin x} \right)$, we get,
$2\sin x\left( {\cos x} \right)$
Now, we know the double angle formula for sine function as $\sin 2x = 2\sin x\cos x$. So, we get $\sin 2x$.
So, the derivative of $\left( {{{\sin }^2}x} \right)$ with respect to $x$ is $\sin 2x$.
Note: The derivatives of basic trigonometric functions must be learned by the heart in order to find derivatives of complex composite functions using the chain rule of differentiation. The chain rule of differentiation involves differentiating a composite by introducing new unknowns to ease the process and examine the behavior of function layer by layer. The answer to the problem can also be $2\sin x\left( {\cos x} \right)$, but it is better to use the double angle formula of the sine function and give a precise final answer.
Complete step by step answer:
So, Derivative of $\left( {{{\sin }^2}x} \right)$ with respect to $x$can be calculated as $\dfrac{d}{{dx}}\left( {{{\sin }^2}x} \right)$ .
Now, $\dfrac{d}{{dx}}\left( {{{\sin }^2}x} \right)$
Taking the power outside the bracket in order to apply chain rule of differentiation.
\[\dfrac{d}{{dx}}\left[ {{{\left( {\sin x} \right)}^2}} \right]\]
Now, Let us assume $u = \sin (x)$. So substituting $\sin (x)$ as $u$, we get,
$\dfrac{d}{{dx}}{\left[ u \right]^2} = 2u\dfrac{{du}}{{dx}}$
Now, putting back $u$ as $\sin (x)$, we get,
$2\sin x\dfrac{{d\left( {\sin x} \right)}}{{dx}}$ because \[\dfrac{{du}}{{dx}} = \dfrac{{d(\sin x)}}{{dx}}\]
Now, we know that the derivative of $\sin x$ with respect to $x$ is \[\cos x\]. So, $\dfrac{d}{{dx}}\left( {\sin x} \right) = \cos x$.
So, Substituting the equivalent expression of $\dfrac{d}{{dx}}\left( {\sin x} \right)$, we get,
$2\sin x\left( {\cos x} \right)$
Now, we know the double angle formula for sine function as $\sin 2x = 2\sin x\cos x$. So, we get $\sin 2x$.
So, the derivative of $\left( {{{\sin }^2}x} \right)$ with respect to $x$ is $\sin 2x$.
Note: The derivatives of basic trigonometric functions must be learned by the heart in order to find derivatives of complex composite functions using the chain rule of differentiation. The chain rule of differentiation involves differentiating a composite by introducing new unknowns to ease the process and examine the behavior of function layer by layer. The answer to the problem can also be $2\sin x\left( {\cos x} \right)$, but it is better to use the double angle formula of the sine function and give a precise final answer.
Recently Updated Pages
Master Class 12 Business Studies: Engaging Questions & Answers for Success

Master Class 12 Biology: Engaging Questions & Answers for Success

Master Class 12 Chemistry: Engaging Questions & Answers for Success

Class 12 Question and Answer - Your Ultimate Solutions Guide

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Trending doubts
Which is more stable and why class 12 chemistry CBSE

Which are the Top 10 Largest Countries of the World?

Draw a labelled sketch of the human eye class 12 physics CBSE

Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE

What are the major means of transport Explain each class 12 social science CBSE

Sulphuric acid is known as the king of acids State class 12 chemistry CBSE

