Question

What is the difference between carbon dioxide, and silicon dioxide? How do we formulate the solubility product for the salt $ {A_2}{B_3} $ .

Answer 1

Hint: Carbon and silicon both belong to the same group of chemical elements in the periodic table, but their oxides have very different nature. As carbon dioxide is a gas, and silicon dioxide is a strong solid at standard temperature. The solubility product for the salt $ {A_2}{B_3} $ can be written in terms of coefficients and concentrations of ions in that salt.

Complete Step By Step Answer:
In the periodic table the elements that belong to group $ 14 $ are carbon, silicon, germanium, tin, and lead. Carbon forms oxides like carbon dioxide with oxygen forms carbon dioxide with the molecular formula of $ C{O_2} $ and silicon forms oxides like silicon dioxide with oxygen with the molecular formula of $ Si{O_2} $ .
But carbon dioxide is in linear geometry and exists as a gas at standard temperature. Whereas silicon dioxide exists as a solid as the silicon and oxygen in silicon dioxide binds with other silicon dioxide forms a polymer like chain with tetrahedral geometry.
Salts are the ionic chemical compounds that were formed from the cations mostly alkali and alkaline earth metals and anions mostly carbonate and phosphate groups.
The salt $ {A_2}{B_3} $ has the dissociation as:
 $ {A_2}{B_3} \rightleftharpoons 2{A^ + } + 3{B^ - } $
Thus, the equilibrium constant can be written as $ {K_{sp}} = {\left[ A \right]^2}{\left[ B \right]^3} $ .

Note:
Examples of salt that were in the form of $ {A_2}{B_3} $ are $ F{e_2}{\left( {S{O_4}} \right)_3} $ that was dissociated to give ferrous ion and sulphate ion. The equilibrium constant of ferrous sulphate can be written in terms of the concentrations of $ F{e^{ + 2}} $ and $ S{O_4}^{ - 3} $ , the equilibrium constant can be written as $ {\left[ {F{e^{ + 2}}} \right]^2}{\left[ {S{O_4}^{ - 3}} \right]^3} $