Question

D-glucose and D-fructose both form the same osazone. Which statements are correct about the above reaction?
This question has multiple correct options
A. glucose and Fructose are epimers
B. glucose and Fructose are anomers
C. the configuration of the OH group at C - 3 and C - 4 in glucose and Fructose are same
D. the configuration of the OH group at C - 4 and C - 5 in glucose and Fructose are same

Answer 1

Hint: in the question given that dextrose glucose and fructose can form similar types of osazone. So, from the given statement we have to recognize the correct one and explain the reason. As D-glucose and D-fructose are constitutional isomers. And share the same molecular formula ${C_6}{H_{12}}{O_6}$.


Complete Step by step answer: From the above statements
Epimers are diastereomers that contain more than one chiral center but differ from each other in the complete configuration at only one chiral center.
Glucose and fructose are not epimers. Thus option (A) is incorrect.
An anomer is a distinct type of epimer in which one of two stereoisomers of a cyclic saccharide differs only in its configuration at the acetal carbon, also called the anomeric carbon.
Glucose and fructose are not anomers. Thus option (B) is incorrect.
The configurations of the \[OH\]group at \[C - 3{\text{ }}and{\text{ }}C - 4\] in glucose and fructose are the same.
Thus option (C) is correct.
The configurations of the OH group at \[C - 4{\text{ }}and{\text{ }}C - 5\] in glucose and fructose are the same.
Thus option (D) is correct.

Hence, the statement C and D are correct.

Note: As Osazone are highly colored and crystalline complexes and can be easily detected. Each different osazone has a characteristic crystal formation Such as from glucose, fructose it forms broomstick or needle-shaped crystals.