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Derive the formula for heat produced in a wire carrying current (I), resistance (R) in time (t).

Answer
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Hint: The work done in a circuit by a battery can be assumed to dissipate as heat energy. Therefore, the work done is heat energy. Using Ohm’s Law and work done we can find a relationship between current (I), resistance (R), potential difference (V) and time (t).

Formula used:
R=VI
W=QV

Complete step by step solution:
The rate of flow of electrons in a conductor is called current (I). Its SI unit is ampere (A ).
The property of a material by virtue of which it resists the current flowing through it is called resistance (R). Its SI unit is ohm (Ω).
I=Qt -------- (1)
The work done to carry a unit charge from one point to the other is called Potential difference (V) between the two points.
V=VbVa ------------ (2)
According to Ohm’s Law-
R=VI ------------- (3)
The work done, Wby the battery to move charge Qin a circuit with potential difference Vapplied at its ends is-
W=QV ------------ (4)
From eq (1),
Q=I×t Substituting in eq (4)
W=(I×t)V ------------ (5)
From eq (3), we have,
V=IR Substituting in eq (5)
W=It×IRW=I2Rt
Assuming that all the electrical work is converted into heat energy, then
W=H
Here, H is the heat produced in the circuit.
H=I2Rtjoules
This relation is called the Joules Law of Heating.

Note: Using relationships from ohm’s law, the derived formula for heat energy can also be written as-
H=V2Rt , H=VIt. Heat is a form of energy, therefore its SI unit is joules. Most of this heat is developed in the resistor and dissipated into the air around its components.

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