
Current density in a Cu wire is $2.5\times {{10}^{8}}A{{m}^{-2}}$. If 8A current is flowing through it, diameter of the wire is _ _ _ _ _
A. 0.2mm
B. 0.2cm
C. 0.2m
D. 2mm
Answer
552k+ views
Hint: Current density is a physical quantity related to current electricity. We know that current is the rate of flow of charge with respect to time through a conductor. Current density is defined as the amount of current flowing through per unit area of a cross section.
Formula used:
$J=\dfrac{i}{A}$
$A=\pi {{\left( \dfrac{d}{2} \right)}^{2}}$
Complete step by step answer:
Let us first understand what is meant by the quantity current density. Current density is defined as the amount of current flowing through per unit area of a cross section. Suppose we have a wire of some cross section and let a current be flowing through this wire, then if the current is uniform then the current density is equal to the ratio of the current in the wire to the area of the cross section of the wire. If the cross sectional area of the wire is A and the current flowing in it is i, then the current density is given as $J=\dfrac{i}{A}$ ….. (i)
In the given case, the cross section of the Cu wire in circular and the area of a circle is given to be $A=\pi {{\left( \dfrac{d}{2} \right)}^{2}}$, where d is the diameter of the cross section.It is given that current density in the wire is $2.5\times {{10}^{8}}A{{m}^{-2}}$ and the current flowing in it is 8A. This means that, $J=2.5\times {{10}^{8}}A{{m}^{-2}}$ and $i=8A$.
Substitute the values of J, i and A in (i).
$2.5\times {{10}^{8}}=\dfrac{8}{\pi {{\left( \dfrac{d}{2} \right)}^{2}}}$.
$\Rightarrow 2.5\times {{10}^{8}}=\dfrac{8\times 4}{\pi {{d}^{2}}}$
$\Rightarrow {{d}^{2}}=\dfrac{8\times 4}{\pi 2.5\times {{10}^{8}}}\\
\Rightarrow {{d}^{2}} =4\times {{10}^{-8}}$
$\Rightarrow d=\sqrt{4\times {{10}^{-8}}}\\
\Rightarrow d =2\times {{10}^{-4}}m\\
\therefore d =0.2mm$.
This means that the diameter of the wire is equal to 0.2 mm.
Hence, the correct option is A.
Note: Current density is considered to be a vector quantity. The direction of current density is taken along the direction of the area vector of the cross section.Area in some cases is considered a vector (called area vector). The area vector is along an axis normal to the area. In the case of current density, the direction of the area vector is in the direction of the flow of the current.
Formula used:
$J=\dfrac{i}{A}$
$A=\pi {{\left( \dfrac{d}{2} \right)}^{2}}$
Complete step by step answer:
Let us first understand what is meant by the quantity current density. Current density is defined as the amount of current flowing through per unit area of a cross section. Suppose we have a wire of some cross section and let a current be flowing through this wire, then if the current is uniform then the current density is equal to the ratio of the current in the wire to the area of the cross section of the wire. If the cross sectional area of the wire is A and the current flowing in it is i, then the current density is given as $J=\dfrac{i}{A}$ ….. (i)
In the given case, the cross section of the Cu wire in circular and the area of a circle is given to be $A=\pi {{\left( \dfrac{d}{2} \right)}^{2}}$, where d is the diameter of the cross section.It is given that current density in the wire is $2.5\times {{10}^{8}}A{{m}^{-2}}$ and the current flowing in it is 8A. This means that, $J=2.5\times {{10}^{8}}A{{m}^{-2}}$ and $i=8A$.
Substitute the values of J, i and A in (i).
$2.5\times {{10}^{8}}=\dfrac{8}{\pi {{\left( \dfrac{d}{2} \right)}^{2}}}$.
$\Rightarrow 2.5\times {{10}^{8}}=\dfrac{8\times 4}{\pi {{d}^{2}}}$
$\Rightarrow {{d}^{2}}=\dfrac{8\times 4}{\pi 2.5\times {{10}^{8}}}\\
\Rightarrow {{d}^{2}} =4\times {{10}^{-8}}$
$\Rightarrow d=\sqrt{4\times {{10}^{-8}}}\\
\Rightarrow d =2\times {{10}^{-4}}m\\
\therefore d =0.2mm$.
This means that the diameter of the wire is equal to 0.2 mm.
Hence, the correct option is A.
Note: Current density is considered to be a vector quantity. The direction of current density is taken along the direction of the area vector of the cross section.Area in some cases is considered a vector (called area vector). The area vector is along an axis normal to the area. In the case of current density, the direction of the area vector is in the direction of the flow of the current.
Recently Updated Pages
Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Business Studies: Engaging Questions & Answers for Success

Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Chemistry: Engaging Questions & Answers for Success

Trending doubts
What are the major means of transport Explain each class 12 social science CBSE

Which are the Top 10 Largest Countries of the World?

Draw a labelled sketch of the human eye class 12 physics CBSE

Explain sex determination in humans with line diag class 12 biology CBSE

The pH of the pancreatic juice is A 64 B 86 C 120 D class 12 biology CBSE

Explain sex determination in humans with the help of class 12 biology CBSE

