How can I convert L-xylose bond line view to Fischer projection?
Answer
574.2k+ views
Hint: We know that using wedge and dash notation, solid lines (sticks) represent chemical bonds in the plane of the surface. Black wedges represent chemical bonds coming toward you, while dashed lines are for bonds that extend back behind the surface.
Complete step by step solution:
A Fischer projection represents every chiral center as a cross. The horizontal line represents bonds extending out of the plane of the paper. The vertical line represents bonds extending behind the plane of the paper. The Fischer projection of L-xylose is
Here's how to convert the wedge-dash structure of L-xylose to its Fischer projection.
Arrange the molecule so that the chiral carbons and the longest continuous chain are in a vertical line. $ C-1 $ (the aldehyde group) goes at the top.
Draw horizontal lines to make crosses at $ C-2,\text{ }C-3, $ and $ C-4. $
Put the $ C-4\text{ }OH $ group on the correct side of the cross. We must view the molecule from the correct angle. This is an L-sugar, so the $ OH $ must be on the left, and $ C-4 $ must be closest to our eye. We must view the molecule from the lower left. We put the $ OH $ on the left arm of the cross. The $ H $ atom goes on the right.
Put the $ C-3\text{ }OH $ group on the correct side of the cross. The $ OH $ is on the left, but $ C-3 $ is furthest from our eye. We must rotate $ C-3 $ to bring it near our eye. The $ OH $ then rotates to the right. We put the $ OH $ on the right arm of the cross. The $ H $ atom goes on the left.
Put the $ C-2\text{ }OH $ group on the correct side of the cross. The $ OH $ group is on the left, and $ C-2 $ is closest to our eye. We put the $ OH $ on the left arm of the cross. The $ H $ atom goes on the right. We now have the Fischer projection of L-xylose.
Note:
Remember that the wedges are now on the right, and the dashes are on the left. It is as if we had wrapped the chain around a cylindrical tube. When you flatten the structure onto the surface of the cylinder, you get the Fischer projection of D-glucose. Understanding the concept of wedge and dash helps to understand stereochemistry and spectroscopy which is an important aspect in research.
Complete step by step solution:
A Fischer projection represents every chiral center as a cross. The horizontal line represents bonds extending out of the plane of the paper. The vertical line represents bonds extending behind the plane of the paper. The Fischer projection of L-xylose is
Here's how to convert the wedge-dash structure of L-xylose to its Fischer projection.
Arrange the molecule so that the chiral carbons and the longest continuous chain are in a vertical line. $ C-1 $ (the aldehyde group) goes at the top.
Draw horizontal lines to make crosses at $ C-2,\text{ }C-3, $ and $ C-4. $
Put the $ C-4\text{ }OH $ group on the correct side of the cross. We must view the molecule from the correct angle. This is an L-sugar, so the $ OH $ must be on the left, and $ C-4 $ must be closest to our eye. We must view the molecule from the lower left. We put the $ OH $ on the left arm of the cross. The $ H $ atom goes on the right.
Put the $ C-3\text{ }OH $ group on the correct side of the cross. The $ OH $ is on the left, but $ C-3 $ is furthest from our eye. We must rotate $ C-3 $ to bring it near our eye. The $ OH $ then rotates to the right. We put the $ OH $ on the right arm of the cross. The $ H $ atom goes on the left.
Put the $ C-2\text{ }OH $ group on the correct side of the cross. The $ OH $ group is on the left, and $ C-2 $ is closest to our eye. We put the $ OH $ on the left arm of the cross. The $ H $ atom goes on the right. We now have the Fischer projection of L-xylose.
Note:
Remember that the wedges are now on the right, and the dashes are on the left. It is as if we had wrapped the chain around a cylindrical tube. When you flatten the structure onto the surface of the cylinder, you get the Fischer projection of D-glucose. Understanding the concept of wedge and dash helps to understand stereochemistry and spectroscopy which is an important aspect in research.
Recently Updated Pages
The given figure shows two endocrine glands marked class 11 biology NEET_UG

Match columnI with columnII and select the correct class 11 biology NEET

Match column I with column II and select the correct class 11 biology NEET_UG

Which floral family has left 9 right + 1 arrangement class 11 biology NEET_UG

Which is not a variety of sheep A Lohi B Beetal C Nellore class 11 biology NEET_UG

Match column I with column II and select the correct class 11 biology NEET_UG

Trending doubts
Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Two of the body parts which do not appear in MRI are class 11 biology CBSE

1 ton equals to A 100 kg B 1000 kg C 10 kg D 10000 class 11 physics CBSE

10 examples of law on inertia in our daily life

