
How to convert from \[N.S/{{m}^{2}}\] to \[N.S/c{{m}^{2}}\] ?
Answer
515.4k+ views
Hint: Unit conversion is the process of converting different units of measurement for the same quantity, typically using multiplicative conversion factors.
Complete step-by-step answer:
A conversion factor is used to accomplish this. A conversion factor is used in mathematics, specifically algebra, to convert a measured quantity to a different unit of measure without changing the relative amount. To accomplish this, a one-to-one ratio (fraction) is established (1).so, to convert the particular number we require following steps,
Calculate the conversion as a fraction (that equals one)
Multiply it by two (leaving all units in the answer)
Cancel any units that are both at the top and bottom of the list.
To give you a better idea of what I'm talking about, let's start with 25 units of the first and convert them to the second.
\[\dfrac{25N\cdot s}{{{m}^{2}}}.{{\left( \dfrac{m}{100cm} \right)}^{2}}\approx \dfrac{{{2.5.10}^{-3}}N.s}{c{{m}^{2}}}\]
Here, in above equation we have taken \[100cm\] on the place of \[{{m}^{2}}\] because we know
\[1m=100cm\] .
The only unit that changes is the bottom, so just connect the two!
Note: The Newton Second Per Square Meter \[\left( N.s/{{m}^{2}} \right)\] is a unit of dynamic viscosity. It is also referred to as newton/second-square meter. The dimension of a Newton Second Per Square Meter \[\left( N.s/{{m}^{2}} \right)\] ) is \[M{{L}^{-1}}{{T}^{-1}}\] , where M is mass, L is length, and T is time. It is nearly identical to the corresponding standard SI unit \[p{{a}^{-s}}\] .
Complete step-by-step answer:
A conversion factor is used to accomplish this. A conversion factor is used in mathematics, specifically algebra, to convert a measured quantity to a different unit of measure without changing the relative amount. To accomplish this, a one-to-one ratio (fraction) is established (1).so, to convert the particular number we require following steps,
Calculate the conversion as a fraction (that equals one)
Multiply it by two (leaving all units in the answer)
Cancel any units that are both at the top and bottom of the list.
To give you a better idea of what I'm talking about, let's start with 25 units of the first and convert them to the second.
\[\dfrac{25N\cdot s}{{{m}^{2}}}.{{\left( \dfrac{m}{100cm} \right)}^{2}}\approx \dfrac{{{2.5.10}^{-3}}N.s}{c{{m}^{2}}}\]
Here, in above equation we have taken \[100cm\] on the place of \[{{m}^{2}}\] because we know
\[1m=100cm\] .
The only unit that changes is the bottom, so just connect the two!
Note: The Newton Second Per Square Meter \[\left( N.s/{{m}^{2}} \right)\] is a unit of dynamic viscosity. It is also referred to as newton/second-square meter. The dimension of a Newton Second Per Square Meter \[\left( N.s/{{m}^{2}} \right)\] ) is \[M{{L}^{-1}}{{T}^{-1}}\] , where M is mass, L is length, and T is time. It is nearly identical to the corresponding standard SI unit \[p{{a}^{-s}}\] .
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