
How do you convert $ {180^ \circ } $ F to Celsius?
Answer
528.6k+ views
Hint: In order to convert $ {180^ \circ } $ F to Celsius, we use the basic formula used for conversion of Celsius to Fahrenheit and Fahrenheit to Celsius and the formula is: $ {T_{^ \circ F}} = {T_{^ \circ c}} \times \dfrac{9}{5} + 32 $ . Just put the value given, solve the equations step by step to find the Celsius value.
Complete step by step solution:
We are given $ {180^ \circ } $ Fahrenheit.
From the conversion formulas of temperature, we know that:
$ {T_{^ \circ F}} = {T_{^ \circ c}} \times \dfrac{9}{5} + 32 $
We have the degree in Fahrenheit value with us, so just put it in the above formula and we get:
$
{T_{^ \circ F}} = {T_{^ \circ c}} \times \dfrac{9}{5} + 32 \\
{180^ \circ } = {T_{^ \circ c}} \times \dfrac{9}{5} + 32 \;
$
Since, we need the Celsius value so we have to separate it on one side and for that we need to remove or solve the extra parts from one side. Let’s solve it step by step:
Subtract both the sides by $ 32 $ :
$
180 - 32 = {T_{^ \circ c}} \times \dfrac{9}{5} + 32 - 32 \\
148 = {T_{^ \circ c}} \times \dfrac{9}{5} \;
$
Multiply both sides by $ 5 $ :
$
148 = {T_{^ \circ c}} \times \dfrac{9}{5} \\
148 \times 5 = {T_{^ \circ c}} \times \dfrac{9}{5} \times 5 \\
740 = {T_{^ \circ c}} \times 9 \;
$
And for the last step to separate the Celsius value, divide both the sides by $ 5 $ and we get:
$
740 = {T_{^ \circ c}} \times 9 \\
\dfrac{{740}}{9} = \dfrac{{{T_{^ \circ c}} \times 9}}{9} \\
82.22 = {T_{^ \circ c}} \;
$
And, we get: $ {T_{^ \circ c}} = 82.22 $ .
Therefore, $ {180^ \circ } $ Fahrenheit in Celsius is $ {82.22^ \circ } $ .
So, the correct answer is “$ {82.22^ \circ } $”.
Note: If instead of Fahrenheit, Celsius was needed to be found then also follow the same steps just put the value given in their respective place in the formula.
For these kinds of conversions, always try to solve step by step for ease, rather than putting the value and solving it at once.
Celsius, written as $ ^ \circ C $ is also called as Centigrade and is the most common Temperature to be used in the world from all the four temperature scales available.
Complete step by step solution:
We are given $ {180^ \circ } $ Fahrenheit.
From the conversion formulas of temperature, we know that:
$ {T_{^ \circ F}} = {T_{^ \circ c}} \times \dfrac{9}{5} + 32 $
We have the degree in Fahrenheit value with us, so just put it in the above formula and we get:
$
{T_{^ \circ F}} = {T_{^ \circ c}} \times \dfrac{9}{5} + 32 \\
{180^ \circ } = {T_{^ \circ c}} \times \dfrac{9}{5} + 32 \;
$
Since, we need the Celsius value so we have to separate it on one side and for that we need to remove or solve the extra parts from one side. Let’s solve it step by step:
Subtract both the sides by $ 32 $ :
$
180 - 32 = {T_{^ \circ c}} \times \dfrac{9}{5} + 32 - 32 \\
148 = {T_{^ \circ c}} \times \dfrac{9}{5} \;
$
Multiply both sides by $ 5 $ :
$
148 = {T_{^ \circ c}} \times \dfrac{9}{5} \\
148 \times 5 = {T_{^ \circ c}} \times \dfrac{9}{5} \times 5 \\
740 = {T_{^ \circ c}} \times 9 \;
$
And for the last step to separate the Celsius value, divide both the sides by $ 5 $ and we get:
$
740 = {T_{^ \circ c}} \times 9 \\
\dfrac{{740}}{9} = \dfrac{{{T_{^ \circ c}} \times 9}}{9} \\
82.22 = {T_{^ \circ c}} \;
$
And, we get: $ {T_{^ \circ c}} = 82.22 $ .
Therefore, $ {180^ \circ } $ Fahrenheit in Celsius is $ {82.22^ \circ } $ .
So, the correct answer is “$ {82.22^ \circ } $”.
Note: If instead of Fahrenheit, Celsius was needed to be found then also follow the same steps just put the value given in their respective place in the formula.
For these kinds of conversions, always try to solve step by step for ease, rather than putting the value and solving it at once.
Celsius, written as $ ^ \circ C $ is also called as Centigrade and is the most common Temperature to be used in the world from all the four temperature scales available.
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