Question

How can the conversion of ethyl chloride to ethyl alcohol, can be carried out?

Answer 1

Hint: For the monohydric alcohols that are the alcohols which has only one hydroxyl group attached to them we have many preparation methods for them. The most common method for their preparation is by heating the haloalkane or the alkyl halides with aqueous solution of the sodium hydroxide or the aqueous solution of the potassium hydroxide. These formed alkyl halide then thereby undergoes the process of hydrolysis to form the product.

Complete answer:
> The other methods for the formation of the monohydric alcohols can be by the heating of the alkyl halide with the moist silver oxide.
> As we know that the ethyl chloride is an alkyl halide and the ethyl alcohol is considered as a monohydric alcohol. So on treating ethyl chloride with the aqueous solution of the potassium hydroxide, the formation of the monohydric alcohol that is the formation of ethyl alcohol takes place.
The reaction for them is the following:
${C_2}{H_5}Cl+KOH(aq) \xrightarrow{heat} {C_2}{H_5}OH+ KCl$

> The other method for forming ethyl alcohol from ethyl chloride is by reacting the ethyl chloride with the moist silver oxide which forms the ethyl alcohol.
The reaction for them is the following:
${C_2}{H_5}Cl+AgOH(aq) \xrightarrow{heat} {C_2}{H_5}OH+AgCl$

Note: Now if we treat the alkyl halide with the concentrated alcoholic solution of the potassium hydroxide the hydrogen molecule of the halide will get eliminated and the formation of alkene will take place. If we treat the haloalkanes with the potassium nitrite we see that the formation of the alkyl nitrite occurs. If we treat the haloalkanes with the silver nitrite here we see that the formation of nitroalkanes takes place.