Consider the following statements
(i) Out of two – $N{H_2}$ groups in semicarbazide only one is involved in formation of semicarbazones.
(ii) Cyclohexane forms cyanohydrin in good yield but $2,2,6$−trimethylcyclohexanone does not.
(iii) The $\alpha $−hydrogens in aldehydes and ketones are acidic.
A. I and iii
B. ii and iii
C. I and ii
D. i, ii and iii
Answer
616.2k+ views
Hint:The lone pair on nitrogen atoms is involved in the resonance with the carbonyl group, thus one of them cannot act as a nucleophile. Nucleophile ions cannot easily attack the carbonyl carbon.
Complete step-by-step answer:
The following information given in the question can be stated by:
(i) Out of two -$N{H_2}$ groups in semicarbazide, actually one is a part of amide functional group. In this we can say, the lone pair on the given nitrogen atom is involved in the resonance behaviour with the carbonyl group. Hence, this $N{H_2}$ group cannot act like a nucleophile. Therefore, it is not the one which is involved in the formation of semicarbazones.
(ii) In cyclohexanone, the carbonyl carbon is not actually hindered. Thus, the nucleophile $C{N^ - }$- ion is easily able to attack the carbonyl carbon. Although in $2,2,6$-trimethyl cyclohexanone, the carbonyl carbon is hindered because of the existence of methyl groups. Thus, the nucleophile $C{N^ - }$ion cannot easily attack the carbonyl carbon.
(iii) This is just because of simply the difference b/w the electronegativities of carbon and double bonded oxygen and as we all know oxygen is the second most electronegative element as of which partial positive and partial negative charges both appears and carbon and oxygen respectively due to which dissociation of Alpha hydrogen gets easier as we all know the acidic character is how easily any compound loses H ion. Hence, it shows an acidic character.
Hence, Option B) ii and iii is correct.
Note:Hint should be clearly observed and the options should also be compared, answers can be determined using the hint and options. As nucleophile ions cannot easily attack the carbonyl carbon and also the $\alpha $−hydrogens in aldehydes and ketones are acidic in nature.
Complete step-by-step answer:
The following information given in the question can be stated by:
(i) Out of two -$N{H_2}$ groups in semicarbazide, actually one is a part of amide functional group. In this we can say, the lone pair on the given nitrogen atom is involved in the resonance behaviour with the carbonyl group. Hence, this $N{H_2}$ group cannot act like a nucleophile. Therefore, it is not the one which is involved in the formation of semicarbazones.
(ii) In cyclohexanone, the carbonyl carbon is not actually hindered. Thus, the nucleophile $C{N^ - }$- ion is easily able to attack the carbonyl carbon. Although in $2,2,6$-trimethyl cyclohexanone, the carbonyl carbon is hindered because of the existence of methyl groups. Thus, the nucleophile $C{N^ - }$ion cannot easily attack the carbonyl carbon.
(iii) This is just because of simply the difference b/w the electronegativities of carbon and double bonded oxygen and as we all know oxygen is the second most electronegative element as of which partial positive and partial negative charges both appears and carbon and oxygen respectively due to which dissociation of Alpha hydrogen gets easier as we all know the acidic character is how easily any compound loses H ion. Hence, it shows an acidic character.
Hence, Option B) ii and iii is correct.
Note:Hint should be clearly observed and the options should also be compared, answers can be determined using the hint and options. As nucleophile ions cannot easily attack the carbonyl carbon and also the $\alpha $−hydrogens in aldehydes and ketones are acidic in nature.
Recently Updated Pages
Which of the following graphs shows the variation of class 12 physics CBSE

Draw a labelled diagram of the human male reproductive class 12 biology CBSE

Describe the experiment to compare the emf of two cells class 12 physics CBSE

What is standard hydrogen electrode

What is conventional current and electric current class 12 physics CBSE

2Bromopentane is treated with an alcoholic KOH solution class 12 chemistry CBSE

Trending doubts
Materials which do not allow an electric current to class 12 physics CBSE

Which is the strongest oxidising agent out of the following class 12 chemistry CBSE

In which of the following devices Eddy current is not class 12 physics CBSE

Draw a well labelled diagram of the human brain class 12 biology CBSE

Draw a well labelled diagram of LS of the human ki class 12 biology CBSE

Which of the following are not electromagnetic waves class 12 physics CBSE

