
Complete the table based on the amperage of the fuse wire.
Electrical device Operating voltage (V) Power of the device (P) Current through the circuit
I=P/V The amperage of the fuse to be used in the circuit (A) Water heater 230 V 4370 W 20 A Air conditioner (AC) 230 V 3335 W 15 A Television (LED-TV) 230 V 57.5 W 0.3 A Computer (Laptop) 230 V 28.75 W 0.2 A
| Electrical device | Operating voltage (V) | Power of the device (P) | Current through the circuit I=P/V | The amperage of the fuse to be used in the circuit (A) |
| Water heater | 230 V | 4370 W | 20 A | |
| Air conditioner (AC) | 230 V | 3335 W | 15 A | |
| Television (LED-TV) | 230 V | 57.5 W | 0.3 A | |
| Computer (Laptop) | 230 V | 28.75 W | 0.2 A |
Answer
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Hint: In the given table, we are given the electrical devices with their operating voltage and power consumption. We need to complete the third column for current through the circuit which is equal to the power consumed by the device divided by the operating voltage of the device.
Complete step by step answer:
The power consumed by an electrical circuit is equal to the product of operating voltage of that device and the magnitude of the current flowing through the circuit due to that device. Therefore, the current through an electrical circuit is equal to the power divided by the voltage. Using this formula we can calculate the current for all the devices given in the table.
1. For the water heater, we have voltage $V = 230V$ and the power consumed is given as $P = 4370W$. Therefore the current through the circuit due to the water heater is given as
$I = \dfrac{P}{V} = \dfrac{{4370}}{{230}} = 19A$
2. For the air conditioner, we have voltage $V = 230V$ and the power consumed is given as $P = 3335W$. Therefore the current through the circuit due to the air conditioner is given as
$I = \dfrac{P}{V} = \dfrac{{3335}}{{230}} = 14.5A$
3. For the television, we have voltage $V = 230V$ and the power consumed is given as $P = 57.5W$. Therefore the current through the circuit due to the television is given as
$I = \dfrac{P}{V} = \dfrac{{57.5}}{{230}} = 0.25A$
4. For the computer, we have voltage $V = 230V$ and the power consumed is given as $P = 28.75W$. Therefore the current through the circuit due to the computer is given as
$I = \dfrac{P}{V} = \dfrac{{28.75}}{{230}} = 0.125A$
Therefore, now the complete table is given as
Note: The value of amperage of the fuse is crucial for protecting the circuit. When the current in the circuit exceeds the amperage of the fuse then the fuse melts, cutting off the flow of current in the circuit. It should be noted that the amperage values are slightly larger than the current through the circuit for respective devices.
Complete step by step answer:
The power consumed by an electrical circuit is equal to the product of operating voltage of that device and the magnitude of the current flowing through the circuit due to that device. Therefore, the current through an electrical circuit is equal to the power divided by the voltage. Using this formula we can calculate the current for all the devices given in the table.
1. For the water heater, we have voltage $V = 230V$ and the power consumed is given as $P = 4370W$. Therefore the current through the circuit due to the water heater is given as
$I = \dfrac{P}{V} = \dfrac{{4370}}{{230}} = 19A$
2. For the air conditioner, we have voltage $V = 230V$ and the power consumed is given as $P = 3335W$. Therefore the current through the circuit due to the air conditioner is given as
$I = \dfrac{P}{V} = \dfrac{{3335}}{{230}} = 14.5A$
3. For the television, we have voltage $V = 230V$ and the power consumed is given as $P = 57.5W$. Therefore the current through the circuit due to the television is given as
$I = \dfrac{P}{V} = \dfrac{{57.5}}{{230}} = 0.25A$
4. For the computer, we have voltage $V = 230V$ and the power consumed is given as $P = 28.75W$. Therefore the current through the circuit due to the computer is given as
$I = \dfrac{P}{V} = \dfrac{{28.75}}{{230}} = 0.125A$
Therefore, now the complete table is given as
| Electrical device | Operating voltage (V) | Power of the device (P) | Current through the circuit I=P/V | The amperage of the fuse to be used in the circuit (A) |
| Water heater | 230 V | 4370 W | 19 A | 20 A |
| Air conditioner (AC) | 230 V | 3335 W | 14.5 A | 15 A |
| Television (LED-TV) | 230 V | 57.5 W | 0.25 A | 0.3 A |
| Computer (Laptop) | 230 V | 28.75 W | 0.125 A | 0.2 A |
Note: The value of amperage of the fuse is crucial for protecting the circuit. When the current in the circuit exceeds the amperage of the fuse then the fuse melts, cutting off the flow of current in the circuit. It should be noted that the amperage values are slightly larger than the current through the circuit for respective devices.
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