Question

Complete the following reaction: Sulphuric acid + Ammonium hydroxide
A. No reaction
B. Ammonium sulfite +Water
C. Ammonium sulfate + Water
D. Ammonium sulfide + Water

Answer 1

Hint: Ammonium hydroxide is a base, when it reacts with sulfuric acid-base reaction will happen. The formula of ammonium hydroxide and sulfuric acid are, \[N{H_4}OH\,,\,{H_2}S{O_4}\]. Ammonium hydroxide is a weak base, but sulfuric acid is a strong acid.

Complete step by step answer:
In his reaction between ammonium hydroxide and sulfuric acid, water salt will be formed. The reaction is shown below,
 \[2N{H_4}OH\, + {H_2}S{O_4} \to {\left( {N{H_4}} \right)_2}S{O_4} + 2{H_2}O\]
In this reaction Ammonium sulfate and Water is formed.

So, the correct answer is C.
Additional information:

Sodium acetate is the sodium salt of acetic acid, which can be formed by the reaction of sodium hydroxide which is a base and acetic acid. They undergo an acid-base reaction and form salt and water. The reaction is shown below,
 \[NaOH\, + C{H_3}COOH \to C{H_3}COONa + {H_2}O\]
The aqueous solution of aluminum chloride is a salt of the weak acid and strong hydrochloride salt, the reaction is shown below,
 \[HCl\, + N{H_4}OH \to N{H_4}Cl + {H_2}O\]
When aluminum chloride salt is added in a water solvent. it partially dissociates and its cation on reacting releases hydrogen ions. Writing a balanced chemical reaction can specify it. This is called hydrolysis of salt.
Aluminum chloride on reacting with water results in the formation of aluminum hydroxide and hydrochloric acid. The chemical equation of the reaction is:
 \[AlC{l_3} + 3{H_2}O \to Al{(OH)_3} \downarrow + 3HCl\]
Here, aluminum hydroxide is a weak base i.e. it partially dissociates in the solution and is sparingly soluble in water, and therefore it is in precipitate form. Hydrochloric acid is a strong acid and can completely dissociate into respective cation and anion, \[{H^ + }\] and \[C{l^ - }\].

Note:
Ammonium sulfate can also be prepared from the reaction between \[N{H_3}\] and \[{H_2}S{O_4}\]. In this reaction, one mole of \[{H_2}S{O_4}\] reacts with two moles of \[N{H_3}\]. As ammonia is a base it absorbs hydrogen ion and forms ammonium ion. Then it combines with the sulfate anion to form the ionic inorganic salt ammonium sulfate. The reaction is shown below.
 \[{H_2}S{O_4} + 2N{H_3} \to 2N{H_4}^ + + S{O_4}^{ - 2} \to {\left( {N{H_4}} \right)_2}S{O_4}\]