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# Complete the following equation$Xe{F_2} + {H_2}O \to$ Verified
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Hint: We have to know when a water molecule is present in the reaction as one of the reactants, we call the reaction a hydrolysis reaction. We have to know the term “hydrolysis” is derived from Greek word hydro which means water and lysis means to break (or) to bind. In simple words, water is used to break down the chemical bonds that are found between specific substances.

$Xe{F_2}\left( s \right) + {H_2}O\left( l \right) \to Xe\left( g \right) + HF\left( {aq} \right) + {O_2}\left( g \right)$
We can see that the above reaction is unbalanced. We need two moles of $Xe{F_2}$ in the reactant side, two moles of $Xe$ and two moles of $HF$ in the product side to make the equation a balanced one.
$2Xe{F_2}\left( s \right) + 2{H_2}O\left( l \right) \to 2Xe\left( g \right) + 4HF\left( {aq} \right) + {O_2}\left( g \right)$