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Complete the below reaction-
$Ca{\left( {OH} \right)_2} + HF \to $
A) $Ca{\left( {OH} \right)_2} + HF \to 2{H_2}O + Ca{F_2}$
B) $Ca{\left( {OH} \right)_2} + HF \to 2{H_2}O + 2Ca{F_2}$
C) $2Ca{\left( {OH} \right)_2} + 2HF \to {H_2}O + 2Ca{F_2}$
D) $Ca{\left( {OH} \right)_2} + 2HF \to 2{H_2}O + Ca{F_2}$

Answer
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Hint: We know that a neutralization response can be characterized as a substance response where an acid and base quantitatively respond together to frame a salt and water as a product. In science, neutralization is a substance response wherein acid and a base respond quantitatively with one another. In a response in water, neutralization results in there being no overabundance of hydrogen or hydroxide particles present in the arrangement. The pH of the neutral arrangement relies upon the acid strength of the reactants.

Complete answer:
We know that calcium hydroxide is a base and hydrogen fluoride is an acid hence the given reaction is a neutralization reaction. The product formed by the reaction is water and calcium fluoride.
The complete equation is,
$Ca{\left( {OH} \right)_2} + 2HF \to 2{H_2}O + Ca{F_2}$

Hence, option D is correct.

Note:
We have to know that a neutralization response is the point at which an acid and a base respond to frame water and a salt and includes the blend of \[{H^ + }\] particles and \[O{H^ - }\] particles to create water. The neutralization of a solid acid and solid base has a pH equivalent to\[7\]. The neutralization of a solid acid and powerless base will have a pH of under\[7\], and alternately, the subsequent pH when a solid base kills a frail acid will be more noteworthy than\[7\].
At the point when an answer is neutral, it implies that salts are framed from equivalent loads of acid and base. The measure of acid required is the sum that would give one mole of protons \[{H^ + }\]and the measure of base required is the sum that would give one mole of \[O{H^ - }\]since salts are framed from neutralization responses with comparable groupings of loads of acids and bases: N parts of acid will consistently neutral N parts of base.