Question

Complete and balance the following chemical reaction:
\[CaC{O_3} + {\text{ }}HCl\; \to ?\]

Answer 1

Hint: On the reactant and product sides of a balanced chemical equation, there are equivalent numbers of atoms for each element involved in the reaction. This is a condition that the equation must meet in order to be consistent with the conservation of matter law. It can be checked by adding the numbers of atoms to both sides of the arrow and comparing them to ensure that they are identical.

Complete answer: On the reactant and product sides of a balanced chemical equation, there are equivalent numbers of atoms for each element involved in the reaction. This is a condition that the equation must meet in order to be consistent with the conservation of matter law. It can be checked by adding the numbers of atoms to both sides of the arrow and comparing them to ensure that they are identical.
Acids produce carbon dioxide, as well as metal salts and water, when they react with metal carbonates or metal bicarbonates. Calcium chloride, carbon dioxide, and water are formed when calcium carbonate reacts with hydrochloric acid. Allowing carbon dioxide gas to flow into lime water turns it milky.
\[CaC{O_3} + 2HCl \to CaC{l_2} + C{O_2} + {H_2}O\]
Calcium chloride is a salt with the molecular formula\[CaC{l_2}\]. It is an inorganic compound. At room temperature, it is a white crystalline solid that is highly soluble in liquids. It's made by mixing calcium hydroxide with hydrochloric acid to neutralise it.
It is a hydrated solid with the generic formula, where x = 0, 1, 2, 4, and 6. De-icing and dust management are two of the most popular applications for these compounds. The anhydrous salt is used as a desiccant since it is hygroscopic.

Note:
Carbon dioxide reacts with limewater (a calcium hydroxide solution, \[Ca{\left( {OH} \right)_2}\]to produce a white calcium carbonate precipitate,\[CaC{O_3}\]. When more carbon dioxide is added, the precipitate dissolves, becoming a colourless calcium hydrogencarbonate solution.