Question

When cold $NaOH$ reacts with $C{{l}_{2}}$ ​which of the following is formed ?
(A) $NaClO$
(B) $NaCl{{O}_{2}}$
(C) $NaCl{{O}_{3}}$
(D) None

Answer 1

Hint: Different ways exist for sodium chloride and chlorine to react. Different reactions occur when $NaOH$is hot and concentrated compared to when something is cold and diluted. We have to write the balanced equation of the reaction between $NaOH$ and $C{{l}_{2}}$ in cold conditions.

Complete step by step solution:
When cold $NaOH$ reacts with $C{{l}_{2}}$​, one of the products formed is$NaClO$.
The reaction between $NaOH$ and $C{{l}_{2}}$ in cold conditions is as shown below:
$2NaOH+Cl_2\rightarrow NaClO + NaCl + H_2O$

This reaction is a disproportionate reaction. A disproportionation reaction is one in which the same element undergoes both oxidation and reduction at the same time. A single chemical produces two products in this kind of reaction, one of which is oxidised and the other is reduced. In the given reaction, chlorine gas and cold, diluted sodium hydroxide react disproportionately.

Oxidation and reduction of chlorine gas produce the ions $OC{{l}^{-}}$ and $C{{l}^{-}}$, respectively. Water, sodium chloride, and sodium hypochlorite are the products formed.
Correct Option: (A) $NaClO$.

Additional Information: Bleach, also known as sodium hypochlorite, is most commonly used as a disinfectant. It is a multipurpose disinfectant that kills mycobacterium, bacteria, fungi, viruses, and other microorganisms. It can be applied to the wounded region by pouring or spraying. With the addition of sodium hypochlorite, the pH of water rises.

Note: The reaction conditions should be kept in mind as the reaction between $NaOH$ and $C{{l}_{2}}$ in cold conditions gives $NaClO$ while when $NaOH$ and $C{{l}_{2}}$ in hot conditions gives$NaCl{{O}_{3}}$.