
Coke powder is spread over the molten electrolyte to:
(A)- prevent the heat radiation from the surface
(B)- prevent the corrosion of graphite anode
(C)- prevent the oxidation of molten aluminum by air
(D)- both (a) and (b)
Answer
579k+ views
Hint: Coke acts as a reducing agent. Reducing agents prevent oxidation reactions like burning, corrosion. Electrolysis reduction of aluminium is carried out in a cell made of iron using carbon electrodes. The temperature inside the electrolytic cell is very high.
Complete step by step solution:
Aluminium is obtained by the electrolysis of alumina ($A{{l}_{2}}{{O}_{3}}$) mixed with cryolite ($N{{a}_{3}}Al{{F}_{6}}$). This process is known as Hall and Heroult’s process. The molten mass to be electrolyzed, which is formed by the mixing of alumina and cryolite, is covered with a layer of powdered coke. The role of coke in the process of electrolysis is twofold.
The molten electrolyte has to be maintained at high temperature inside the bath. Layer of powdered coke on the molten electrolyte acts as insulation and does not allow the heat to dissipate. So, coke reduces or prevents the loss of heat due to radiation from the surface.
Graphite is used as anode. The reactions taking place at anode and cathode during the electrolytic reduction of alumina are given below:
At cathode: \[2A{{l}_{2}}{{O}_{3}}\to 4Al+3{{O}_{2}}\] or $A{{l}^{3+}}(melt)+3{{e}^{-}}\to Al$
At anode: \[\begin{align}
& C(s)+{{O}^{2-}}(melt)\to CO(g)+2{{e}^{-}} \\
& C(s)+2{{O}^{2-}}(melt)\to C{{O}_{2}}(g)+4{{e}^{-}} \\
\end{align}\]
Carbon electrode (graphite electrode) reacts with the oxygen released at anode to form carbon dioxide ($C{{O}_{2}}$) and carbon monoxide (CO).
For one kg of aluminum to be obtained, 0.5 kg of graphite anode is burned. That is why the mass at the carbon anode slowly decreases. Coke prevents this burning of graphite electrodes in air (oxygen).
Therefore, we can say that powdered coke prevents loss of heat due to radiation and prevents corrosion of graphite anode.
Hence, the correct option is (D).
Note:
Note that coke prevents the burning or corrosion of graphite electrodes in oxygen. Do not get confused between the options. Coke helps to prevent the oxidation of graphite and it does not prevent the oxidation of aluminium formed.
Complete step by step solution:
Aluminium is obtained by the electrolysis of alumina ($A{{l}_{2}}{{O}_{3}}$) mixed with cryolite ($N{{a}_{3}}Al{{F}_{6}}$). This process is known as Hall and Heroult’s process. The molten mass to be electrolyzed, which is formed by the mixing of alumina and cryolite, is covered with a layer of powdered coke. The role of coke in the process of electrolysis is twofold.
The molten electrolyte has to be maintained at high temperature inside the bath. Layer of powdered coke on the molten electrolyte acts as insulation and does not allow the heat to dissipate. So, coke reduces or prevents the loss of heat due to radiation from the surface.
Graphite is used as anode. The reactions taking place at anode and cathode during the electrolytic reduction of alumina are given below:
At cathode: \[2A{{l}_{2}}{{O}_{3}}\to 4Al+3{{O}_{2}}\] or $A{{l}^{3+}}(melt)+3{{e}^{-}}\to Al$
At anode: \[\begin{align}
& C(s)+{{O}^{2-}}(melt)\to CO(g)+2{{e}^{-}} \\
& C(s)+2{{O}^{2-}}(melt)\to C{{O}_{2}}(g)+4{{e}^{-}} \\
\end{align}\]
Carbon electrode (graphite electrode) reacts with the oxygen released at anode to form carbon dioxide ($C{{O}_{2}}$) and carbon monoxide (CO).
For one kg of aluminum to be obtained, 0.5 kg of graphite anode is burned. That is why the mass at the carbon anode slowly decreases. Coke prevents this burning of graphite electrodes in air (oxygen).
Therefore, we can say that powdered coke prevents loss of heat due to radiation and prevents corrosion of graphite anode.
Hence, the correct option is (D).
Note:
Note that coke prevents the burning or corrosion of graphite electrodes in oxygen. Do not get confused between the options. Coke helps to prevent the oxidation of graphite and it does not prevent the oxidation of aluminium formed.
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