Question

Clayton biked $\dfrac {3} {8} $ of the $14.5$ miles between his house and the beach, how many miles does he still need to bike before he reaches the beach?

Answer 1

Hint: In the above question we have to find the remaining distance which he needs to cover. To find this we first need to calculate the distance he already covered and then subtract it from the total distance. For this let $x$ be the $\dfrac {3} {8} $ part of the $14.5$ miles. And Let $y$ be the remaining distance which he still needs to cover.

Complete step by step solution:
Initially in order to find the distance travelled we will multiply $\dfrac {3} {8} $to the$14.5$then we get,
$\begin {align}
  & \Rightarrow x=\dfrac {3} {8}\times 14.5 \\
 & \Rightarrow x=5.4375 \\
\end{align}$
Now we get the travelled distance $x=5.4375$ miles biked.
Now we have to find the remaining distance which he needs to cover so we need to subtract the covered distance from the total distance.
$\Rightarrow y=$ total - covered
$\begin {align}
  & \Rightarrow y=14.5-5.4375 \\
 & \Rightarrow y=9.0625 \\
\end{align}$
Hence just by using simple ways we got the remaining distance. He needs to travel $9.0625$ miles to reach the beach.

Note:
We can also find the solution by another way.
As we know the total distance is $1$. To find the remaining distance let be $x$, we will subtract the $\dfrac {3} {8} $ from the $1$:
$\begin {align}
  & \Rightarrow x=1-\dfrac {3} {8} \\
 & \Rightarrow x=\dfrac {8-3} {8} \\
 & \Rightarrow x=\dfrac {5} {8} \\
\end{align}$
Now the $\dfrac{5}{8}$th part is need to travel from the total distance so multiply the $\dfrac{5}{8}$ with total distance we get:
$\begin {align}
  & \Rightarrow \dfrac{5}{8}\times 14.5 \\
 & \Rightarrow 9.0625 \\
\end{align}$
Hence we get the exact answer as we got in the above method. We can get the wrong answer if the units of the measurement given are not the same. So make sure to convert in one type of unit.