Question

$C{H_3}COONa$ on reaction with $C{H_3}COCl$ gives:
A.) Acetic anhydride
B.) Methyl acetate
C.) Acetyl chloride
D.) Acetone

Answer 1

Hint: This question can be solved by the concept that when sodium acetate reacts with acetyl halide then acetic anhydride is obtained in the product and sodium halide is obtained as a side product.

Complete step by step answer:
In this question, $C{H_3}COONa$ is the chemical formula of sodium acetate and $C{H_3}COCl$ is the chemical formula of acetyl chloride. When sodium acetate that is ($C{H_3}COONa$)reacts with acetyl chloride that is ($C{H_3}COCl$) then sodium is removed from sodium acetate and chlorine is removed from acetyl chloride and the final product obtained is an acetic anhydride with the removal of sodium chloride. Here, anhydride is any chemical compound which is obtained by elimination of water from another compound. Acetic anhydride is the simplest anhydride of carboxylic acid.
The reaction of sodium acetate and acetyl chloride can be represented as follows:
$C{H_3}COONa + C{H_3}COCl \to C{H_3}COOCOC{H_3} + NaCl$
                                                       Acetic anhydride

So, the correct answer is Option A .

Additional Information:
The acetic anhydride is an organic solvent. It can also be represented as $A{c_2}O$ or ${(C{H_3}CO)_2}O$. It is a highly corrosive element and its contact can burn or irritate the skin. It is used as the major precursor for the production of heroin and is also used in the manufacture of improvised explosive devices(IEDs) Due to which it is banned in many countries.

Note:
Remember that acetic anhydride is also called ethanoic anhydride. This is because acetic anhydride is anhydride of ethanoic acid ($C{H_3}COOH$) formed by the removal of water when two ethanoic acid molecules combine with each other.