
Calculate the volume of $700g$ of alcohol (Take density of alcohol=$0.8gc{m^{ - 3}}$)
Answer
595.2k+ views
Hint- Density is a measure of mass per volume. If two objects are of the same mass, may not have equal density.
Formula used:
$\rho = \dfrac{m}{V}$
Where,
$\rho $=density
$m$=mass
$V$=volume
Complete step by step answer:
Here we have to find the volume of $700g$ of alcohol having density $0.8kgc{m^{ - 3}}$. Lets apply these values in the known formula.
We know that the density is given as the mass divided by the volume and it is written as:
$\rho = \dfrac{m}{V}$
From the given density formula, we can find the volume and it is given as,
$V = \dfrac{m}{\rho }$
$V = \dfrac{{700}}{{0.8}}$
$V = 875c{m^{ - 3}}$
Hence the volume of alcohol, $V = 875c{m^{ - 3}}$.
Additional information:
(i)Density is the property of all matters including solid, liquid and gases. The value of density depends upon the substance it is made up of and its temperature.
(ii)Density decides the object to sink or float. It is the property that floats the ship.
(iii)If the object has high density, it does not float. On the other side if the density of an object is less, objects float.
(iv)High density objects are iron, cement, metals, glass etc. Low density objects are sponge, feather, wood, cork etc.
(v)Density is also determined by the mass and how tightly the molecules are packed together. Low density materials having molecules loosely packed. Whereas the high-density molecules have molecules closely packed.
(v)Volume is a quantity of three-dimensional objects. Its unit is${m^3}$.It has dimensional formula as ${L^3}$.
(vi)Volume is a measure of space occupied in an enclosed surface.
Note: Here we found the volume of alcohol by using the mass and the density of the alcohol. We didn’t convert the unit of density $kgc{m^{ - 3}}$ into $kg{m^{ - 3}}$. Because any other value given is not in metres.
Formula used:
$\rho = \dfrac{m}{V}$
Where,
$\rho $=density
$m$=mass
$V$=volume
Complete step by step answer:
Here we have to find the volume of $700g$ of alcohol having density $0.8kgc{m^{ - 3}}$. Lets apply these values in the known formula.
We know that the density is given as the mass divided by the volume and it is written as:
$\rho = \dfrac{m}{V}$
From the given density formula, we can find the volume and it is given as,
$V = \dfrac{m}{\rho }$
$V = \dfrac{{700}}{{0.8}}$
$V = 875c{m^{ - 3}}$
Hence the volume of alcohol, $V = 875c{m^{ - 3}}$.
Additional information:
(i)Density is the property of all matters including solid, liquid and gases. The value of density depends upon the substance it is made up of and its temperature.
(ii)Density decides the object to sink or float. It is the property that floats the ship.
(iii)If the object has high density, it does not float. On the other side if the density of an object is less, objects float.
(iv)High density objects are iron, cement, metals, glass etc. Low density objects are sponge, feather, wood, cork etc.
(v)Density is also determined by the mass and how tightly the molecules are packed together. Low density materials having molecules loosely packed. Whereas the high-density molecules have molecules closely packed.
(v)Volume is a quantity of three-dimensional objects. Its unit is${m^3}$.It has dimensional formula as ${L^3}$.
(vi)Volume is a measure of space occupied in an enclosed surface.
Note: Here we found the volume of alcohol by using the mass and the density of the alcohol. We didn’t convert the unit of density $kgc{m^{ - 3}}$ into $kg{m^{ - 3}}$. Because any other value given is not in metres.
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