
Calculate the value of resistor $X$.
Answer
552.9k+ views
Hint:In order to solve this question you have to know the concept of Ohm's law which states that the potential difference across the two points is directly proportional to the current through a conductor between that two points. Also, in order to solve this you have to know the equivalent resistance of the resistors connected in series or parallel.
Formula used:
The voltage difference across two points is given by,
$V = IR$
Where, $V$ is the voltage across two points
$I$ is the current through the conductor
$R$ is the resistance
Complete step by step solution:
Here, in this question we have given the voltage across the battery connected, which is given by,
$V = 8V$
And also the current flowing in the circuit is given by,
$I = 0.5A$
In the circuit we have given four resistances which are connected in series and parallel, we have to find the equivalent resistance of all the resistors connected
Firstly, find the equivalent resistance of the three resistors connected in parallel
We know that,
$\dfrac{1}{{{{R'}_{eq}}}} = \dfrac{1}{{{R_1}}} + \dfrac{1}{{{R_2}}} + \dfrac{1}{{{R_3}}}$
On putting the values of all three resistors, we have
$ \Rightarrow \dfrac{1}{{{{R'}_{eq}}}} = \dfrac{1}{4} + \dfrac{1}{{12}} + \dfrac{1}{6}$
On further solving
$ \Rightarrow {R'_{eq}} = 2\Omega $
Now, this $2\Omega $ is in series with $4\Omega $ and $X$.
So, the total equivalent resistance is given by,
${R_{eq}} = 4\Omega + 2\Omega + X$
$ \Rightarrow {R_{eq}} = (6 + X)\Omega $
Now, applying the ohm’s law
According to ohm’s law, we know that the voltage difference across two points is given by,
$V = IR$
Where, $V$ is the voltage across two points
$I$ is the current through the conductor
$R$ is the resistance
On putting all the values we have,
$ \Rightarrow 8 = 0.5 \times \left( {6 + X} \right)$
From the above equation, we have to find the value of $X$
$ \Rightarrow 8 = 3 + 0.5X$
On further solving, we have
$ \Rightarrow X = 10\Omega $
Therefore, the value of resistor $X$ is $10\Omega $.
Note:The equivalent resistance of any circuit is the ratio of the potential difference across the circuit to the total current flowing through the battery or more appropriately the circuit. If the circuit has many resistors then their individual resistances are the ratios of the individual potential differences across them to the individual currents flowing through them.
Formula used:
The voltage difference across two points is given by,
$V = IR$
Where, $V$ is the voltage across two points
$I$ is the current through the conductor
$R$ is the resistance
Complete step by step solution:
Here, in this question we have given the voltage across the battery connected, which is given by,
$V = 8V$
And also the current flowing in the circuit is given by,
$I = 0.5A$
In the circuit we have given four resistances which are connected in series and parallel, we have to find the equivalent resistance of all the resistors connected
Firstly, find the equivalent resistance of the three resistors connected in parallel
We know that,
$\dfrac{1}{{{{R'}_{eq}}}} = \dfrac{1}{{{R_1}}} + \dfrac{1}{{{R_2}}} + \dfrac{1}{{{R_3}}}$
On putting the values of all three resistors, we have
$ \Rightarrow \dfrac{1}{{{{R'}_{eq}}}} = \dfrac{1}{4} + \dfrac{1}{{12}} + \dfrac{1}{6}$
On further solving
$ \Rightarrow {R'_{eq}} = 2\Omega $
Now, this $2\Omega $ is in series with $4\Omega $ and $X$.
So, the total equivalent resistance is given by,
${R_{eq}} = 4\Omega + 2\Omega + X$
$ \Rightarrow {R_{eq}} = (6 + X)\Omega $
Now, applying the ohm’s law
According to ohm’s law, we know that the voltage difference across two points is given by,
$V = IR$
Where, $V$ is the voltage across two points
$I$ is the current through the conductor
$R$ is the resistance
On putting all the values we have,
$ \Rightarrow 8 = 0.5 \times \left( {6 + X} \right)$
From the above equation, we have to find the value of $X$
$ \Rightarrow 8 = 3 + 0.5X$
On further solving, we have
$ \Rightarrow X = 10\Omega $
Therefore, the value of resistor $X$ is $10\Omega $.
Note:The equivalent resistance of any circuit is the ratio of the potential difference across the circuit to the total current flowing through the battery or more appropriately the circuit. If the circuit has many resistors then their individual resistances are the ratios of the individual potential differences across them to the individual currents flowing through them.
Recently Updated Pages
Master Class 12 Business Studies: Engaging Questions & Answers for Success

Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Chemistry: Engaging Questions & Answers for Success

Trending doubts
What are the major means of transport Explain each class 12 social science CBSE

Which are the Top 10 Largest Countries of the World?

Draw a labelled sketch of the human eye class 12 physics CBSE

How much time does it take to bleed after eating p class 12 biology CBSE

Explain sex determination in humans with line diag class 12 biology CBSE

Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE

