
Calculate the total entropy change for the transition at 368K for 1mol of sulphur from the monoclinic to the rhombic solid state, is $\Delta H=-401.7Jmo{{l}^{-1}}$ for the transition. Assume the surroundings to be an ice-water both at $0{}^\circ C$.
(A) $-1.09J{{K}^{-1}}$
(B) $-0.5J{{K}^{-1}}$
(C) $-0.385J{{K}^{-1}}$
(D) None of these
Answer
552.3k+ views
Hint: Think about the property of entropy of a thermodynamic process. We need to calculate the total entropy change for transition of sulphur from monoclinic form to rhombic form. The total entropy change is given as, $\Delta {{S}_{total}}=\Delta {{S}_{system}}+\Delta {{S}_{surroundings}}$. Just substitute the values and find out the answer.
Complete answer:
- According to the second law of thermodynamics, the total entropy change of the system and its surroundings increases in a spontaneous process. Mathematically, for a spontaneous process, $\Delta {{S}_{total}}=\Delta {{S}_{system}}+\Delta {{S}_{surroundings}}$
- Therefore, the total entropy change is the sum of entropy change of system and that of surroundings.
- The entropy change of a system is defined as the change in heat enthalpy per unit temperature in kelvin.
\[\Delta S=\dfrac{\Delta H}{T}\]
- The entropy change for a surrounding is given as,
\[\Delta {{S}_{surroundings}}=-\dfrac{\Delta H}{T}\]
- For the transition of sulphur from monoclinic form to rhombic form, $\Delta H=-401.7Jmo{{l}^{-1}}$.
- The temperature of the monoclinic system, ${{T}_{1}}$ is 368K and of rhombic form, ${{T}_{2}}$ is 273K.
- Therefore, the total change in entropy is given as,
\[\begin{align}
& \Delta {{S}_{total}}=\Delta {{S}_{system}}+\Delta {{S}_{surroundings}} \\
& =\dfrac{\Delta H}{{{T}_{2}}}-\dfrac{\Delta H}{{{T}_{1}}} \\
& =\dfrac{-401.7}{273}-\dfrac{-401.7}{368} \\
& =-1.471+1.092 \\
& \Delta {{S}_{total}}=-0.38J{{K}^{-1}}
\end{align}\]
- Therefore, the total entropy change is -0.38J/K.
Therefore, the correct answer is option (C).
Note:
Remember entropy is a thermodynamic property which gives an idea about the degree of randomness in a system. Entropy depends on change in heat enthalpy and temperature. For spontaneous processes, total entropy change is greater than zero. At equilibrium, total entropy change is zero. For non-spontaneous processes, total entropy change is less than zero.
Complete answer:
- According to the second law of thermodynamics, the total entropy change of the system and its surroundings increases in a spontaneous process. Mathematically, for a spontaneous process, $\Delta {{S}_{total}}=\Delta {{S}_{system}}+\Delta {{S}_{surroundings}}$
- Therefore, the total entropy change is the sum of entropy change of system and that of surroundings.
- The entropy change of a system is defined as the change in heat enthalpy per unit temperature in kelvin.
\[\Delta S=\dfrac{\Delta H}{T}\]
- The entropy change for a surrounding is given as,
\[\Delta {{S}_{surroundings}}=-\dfrac{\Delta H}{T}\]
- For the transition of sulphur from monoclinic form to rhombic form, $\Delta H=-401.7Jmo{{l}^{-1}}$.
- The temperature of the monoclinic system, ${{T}_{1}}$ is 368K and of rhombic form, ${{T}_{2}}$ is 273K.
- Therefore, the total change in entropy is given as,
\[\begin{align}
& \Delta {{S}_{total}}=\Delta {{S}_{system}}+\Delta {{S}_{surroundings}} \\
& =\dfrac{\Delta H}{{{T}_{2}}}-\dfrac{\Delta H}{{{T}_{1}}} \\
& =\dfrac{-401.7}{273}-\dfrac{-401.7}{368} \\
& =-1.471+1.092 \\
& \Delta {{S}_{total}}=-0.38J{{K}^{-1}}
\end{align}\]
- Therefore, the total entropy change is -0.38J/K.
Therefore, the correct answer is option (C).
Note:
Remember entropy is a thermodynamic property which gives an idea about the degree of randomness in a system. Entropy depends on change in heat enthalpy and temperature. For spontaneous processes, total entropy change is greater than zero. At equilibrium, total entropy change is zero. For non-spontaneous processes, total entropy change is less than zero.
Recently Updated Pages
A man running at a speed 5 ms is viewed in the side class 12 physics CBSE

The number of solutions in x in 02pi for which sqrt class 12 maths CBSE

State and explain Hardy Weinbergs Principle class 12 biology CBSE

Write any two methods of preparation of phenol Give class 12 chemistry CBSE

Which of the following statements is wrong a Amnion class 12 biology CBSE

Differentiate between action potential and resting class 12 biology CBSE

Trending doubts
What are the major means of transport Explain each class 12 social science CBSE

Which are the Top 10 Largest Countries of the World?

Draw a labelled sketch of the human eye class 12 physics CBSE

Explain sex determination in humans with line diag class 12 biology CBSE

Explain sex determination in humans with the help of class 12 biology CBSE

Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE

