
How do we calculate the number of sodium ions, $N{a^ + }$ , in $14.2g$ of sodium sulphate? [Relative atomic masses $Na = 23,S = 32,O = 16$ ]?
Answer
543k+ views
Hint: To solve this question, first we will calculate the molar mass of sodium sulphate, then we will find the number of moles present in it. And, finally with the help of no. of moles in sodium sulphate, we can find the number of sodium ions present in $14.2g$ of sodium sulphate.
Complete step-by-step answer:sodium sulphate.First, we will write the chemical formula of Sodium Sulphate, which is $N{a_2}S{O_4}$ .
To find the number of sodium ions in sodium sulphate, first we have to calculate the total number of moles of Sodium Sulphate in a sample.
Here, we have the formula to calculate the number of moles of any compound:
$No.\,of\,moles = \dfrac{{mass\,of\,the\,compound}}{{molar\,mass\,of\,the\,\operatorname{co} compound}}$
In the above formulae, we have already given the mass of the Sodium Sulphate. But we don’t know the molar mass of the Sodium Sulphate.
So, the Molar mass of sodium sulphate is as:
$Molar\,Mass = atomic\,mass\,in\,gram\,s = 2(23) + 32 + 4(16) = 142\,grams\,per\,mole$
Now, we have the molar mass of Sodium Sulphate, so we can find the number of Moles:
$No.\,of\,moles = \dfrac{{14.2g}}{{142gmo{l^{ - 1}}}} = 0.1mol$
Now, for every $1mol$ of $N{a_2}S{O_4}$ we have $2moles$ of $N{a^ + }$ ions.
Multiply the moles of $N{a_2}S{O_4}$ that we found just then by 2 to obtain the moles of sodium ions.
As we know, $6.022 \times {10^{23}}$ is the number of particles or ions in 1mole of any substance. We use Avogadro’s Number to find the number of ions present in any compound.
So, In $1mole$ of $N{a_2}S{O_4}$ , $6.022 \times {10^{23}}$ number of ions are present.
$\therefore $ In $0.2mole$ of $N{a_2}S{O_4}$ , $6.022 \times {10^{23}} \times 0.2\,mol$ number of ions are present, which is $1.2044 \times {10^{23}}ions$ .
Hence, $1.2044 \times {10^{23}}ions$ number of sodium ions, $N{a^ + }$ , present in $14.2g$ of
Note: A mole of a substance or a mole of particles is defined as containing exactly $6.022 \times {10^{23}}particles$ , which may be atoms, molecules, ions, or electrons. This is an experimentally obtained value.
Complete step-by-step answer:sodium sulphate.First, we will write the chemical formula of Sodium Sulphate, which is $N{a_2}S{O_4}$ .
To find the number of sodium ions in sodium sulphate, first we have to calculate the total number of moles of Sodium Sulphate in a sample.
Here, we have the formula to calculate the number of moles of any compound:
$No.\,of\,moles = \dfrac{{mass\,of\,the\,compound}}{{molar\,mass\,of\,the\,\operatorname{co} compound}}$
In the above formulae, we have already given the mass of the Sodium Sulphate. But we don’t know the molar mass of the Sodium Sulphate.
So, the Molar mass of sodium sulphate is as:
$Molar\,Mass = atomic\,mass\,in\,gram\,s = 2(23) + 32 + 4(16) = 142\,grams\,per\,mole$
Now, we have the molar mass of Sodium Sulphate, so we can find the number of Moles:
$No.\,of\,moles = \dfrac{{14.2g}}{{142gmo{l^{ - 1}}}} = 0.1mol$
Now, for every $1mol$ of $N{a_2}S{O_4}$ we have $2moles$ of $N{a^ + }$ ions.
Multiply the moles of $N{a_2}S{O_4}$ that we found just then by 2 to obtain the moles of sodium ions.
As we know, $6.022 \times {10^{23}}$ is the number of particles or ions in 1mole of any substance. We use Avogadro’s Number to find the number of ions present in any compound.
So, In $1mole$ of $N{a_2}S{O_4}$ , $6.022 \times {10^{23}}$ number of ions are present.
$\therefore $ In $0.2mole$ of $N{a_2}S{O_4}$ , $6.022 \times {10^{23}} \times 0.2\,mol$ number of ions are present, which is $1.2044 \times {10^{23}}ions$ .
Hence, $1.2044 \times {10^{23}}ions$ number of sodium ions, $N{a^ + }$ , present in $14.2g$ of
Note: A mole of a substance or a mole of particles is defined as containing exactly $6.022 \times {10^{23}}particles$ , which may be atoms, molecules, ions, or electrons. This is an experimentally obtained value.
Recently Updated Pages
The number of solutions in x in 02pi for which sqrt class 12 maths CBSE

Write any two methods of preparation of phenol Give class 12 chemistry CBSE

Differentiate between action potential and resting class 12 biology CBSE

Two plane mirrors arranged at right angles to each class 12 physics CBSE

Which of the following molecules is are chiral A I class 12 chemistry CBSE

Name different types of neurons and give one function class 12 biology CBSE

Trending doubts
Which are the Top 10 Largest Countries of the World?

What are the major means of transport Explain each class 12 social science CBSE

Draw a labelled sketch of the human eye class 12 physics CBSE

Differentiate between insitu conservation and exsitu class 12 biology CBSE

State the principle of an ac generator and explain class 12 physics CBSE

Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE

