Calculate the molecular weight of cellulose acetate if it's \[0 - 2\% {\text{ }}\left( {wt.{\text{ }}/vol.} \right)\] solution in acetone (sp. gr. 0-8) shows an osmotic rise of 23.1 mm against pure acetone at \[{27^o}C\]
Answer
Verified
400.5k+ views
Hint: The osmotic pressure is the minimum pressure needed to avoid the inward passage of a solution's pure solvent over a semipermeable membrane. It can also be characterised as a measurement of a solution's proclivity to absorb a pure solvent through osmosis. The maximum osmotic pressure that could occur in a solution if it is isolated from its pure solvent by a semipermeable membrane is known as potential osmotic pressure.
Complete answer: The minimum pressure that must be applied to a solution to stop the passage of liquid molecules across a semipermeable membrane is known as osmotic pressure (osmosis). It is a colligative property that is influenced by the solute particle concentration in the solution. The following formula can be used to measure osmotic pressure: \[\pi {\text{ }} = {\text{ }}iCRT\]
A 0.2 $\%$ solution is one of which 0.2 gram of cellulose acetate are dissolved in 100 millilitres of water. 2.31 cm acetone osmotic pressure
\[{\text{P}} = 2.31 \times \dfrac{{0.80}}{{13.6}}\;{\text{cm of Hg}}\]= 0.136g of Hg
\[{\text{P}} = \dfrac{{0.136}}{{76}}\;{\text{atm}}\]
Assume M is the molecular weight of cellulose acetate.
\[{\mathbf{n}} = \dfrac{{0.2}}{{\text{M}}}\]
V = 100 ml = 0.1 L
\[R{\text{ }} = {\text{ }}0.0821{\text{ }}L{\text{ }}atm{\text{ }}mo{l^{ - 1}}{K^{ - 1}}\]
T = 273 + 27 = 300 K
\[{\text{P}} = \dfrac{{{\text{nRT}}}}{{\text{V}}}\]
\[\dfrac{{0.136}}{{76}} = \dfrac{{\dfrac{{0.2}}{M}}}{{0.1}} \times 0.0821 \times 300\]
M = 27500
Note:
The passage of solvent molecules across a semipermeable membrane from a region with low solute concentration to a region with high solute concentration is referred to as osmosis. The two sides of the semipermeable membrane eventually reach a state of equilibrium (equal solute concentration on both sides of the semipermeable membrane).
Complete answer: The minimum pressure that must be applied to a solution to stop the passage of liquid molecules across a semipermeable membrane is known as osmotic pressure (osmosis). It is a colligative property that is influenced by the solute particle concentration in the solution. The following formula can be used to measure osmotic pressure: \[\pi {\text{ }} = {\text{ }}iCRT\]
A 0.2 $\%$ solution is one of which 0.2 gram of cellulose acetate are dissolved in 100 millilitres of water. 2.31 cm acetone osmotic pressure
\[{\text{P}} = 2.31 \times \dfrac{{0.80}}{{13.6}}\;{\text{cm of Hg}}\]= 0.136g of Hg
\[{\text{P}} = \dfrac{{0.136}}{{76}}\;{\text{atm}}\]
Assume M is the molecular weight of cellulose acetate.
\[{\mathbf{n}} = \dfrac{{0.2}}{{\text{M}}}\]
V = 100 ml = 0.1 L
\[R{\text{ }} = {\text{ }}0.0821{\text{ }}L{\text{ }}atm{\text{ }}mo{l^{ - 1}}{K^{ - 1}}\]
T = 273 + 27 = 300 K
\[{\text{P}} = \dfrac{{{\text{nRT}}}}{{\text{V}}}\]
\[\dfrac{{0.136}}{{76}} = \dfrac{{\dfrac{{0.2}}{M}}}{{0.1}} \times 0.0821 \times 300\]
M = 27500
Note:
The passage of solvent molecules across a semipermeable membrane from a region with low solute concentration to a region with high solute concentration is referred to as osmosis. The two sides of the semipermeable membrane eventually reach a state of equilibrium (equal solute concentration on both sides of the semipermeable membrane).
Recently Updated Pages
Master Class 11 English: Engaging Questions & Answers for Success
Master Class 11 Computer Science: Engaging Questions & Answers for Success
Master Class 11 Maths: Engaging Questions & Answers for Success
Master Class 11 Social Science: Engaging Questions & Answers for Success
Master Class 11 Economics: Engaging Questions & Answers for Success
Master Class 11 Business Studies: Engaging Questions & Answers for Success
Trending doubts
10 examples of friction in our daily life
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
State and prove Bernoullis theorem class 11 physics CBSE
Pigmented layer in the eye is called as a Cornea b class 11 biology CBSE
What problem did Carter face when he reached the mummy class 11 english CBSE